看看谁聪明，类游戏寻找算法

 

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不过X点，把所有的圈连起来，不能重复，不能斜连，不能跳圈

 

本人用了游戏寻路算法做了一个程序，没有解出答案，如果差一个圈的有1064个解法。欢迎高手们解答

 

import java.util.ArrayList;

/**
 * @author xtiger ([e-mail]) 2015-09-09 23:39
 */
public class Game {
    private static int[][] t = new int[7][7]; //记录圈子，外围多加一圈，免得判断 ，0：可以走，1：走过，2：不可走
    private static int r[] = new int[25];     //记录结果
    private static int i = 2;                 //当前圈子的x
    private static int j = 1;                 //当前圈子的y
    private static int idx = 0;
    private static int bb = 1;
    private static ArrayList<String> die = new ArrayList<String>(); //记录走不通的路线

    public static void main(String[] args) {

        for (int i = 0; i < 7; i++) {
            for (int j = 0; j < 7; j++) {
                if (i == 0) {
                    t[i][j] = 2;
                }
                if (i == 6) {
                    t[i][j] = 2;
                }
                if (j == 0) {
                    t[i][j] = 2;
                }
                if (j == 6) {
                    t[i][j] = 2;
                }

            }
        }
        t[1][2] = 2;

        t[1][1] = 2;
        t[2][1] = 2;
        r[idx++] = 11;
        r[idx++] = 21;

        while (true) {
            if (up() == 1) continue;
            if (right() == 1) continue;
            if (down() == 1) continue;
            if (left() == 1) continue;
            back();

            int b = 0;
            for (int x = 1; x <= 5; x++) {
                for (int y = 1; y <= 5; y++) {
                    b += t[x][y];
                }
            }
            if (b == 26) {
                echo1();
                continue;
            }
            if (b == 28) break;

        }

        System.out.println("GOOOOOOOOOOD---------------");
        echo1();
    }

    private static int up() {
        if (checkDie((i - 1) * 10 + j)) {
            return 0;
        }
        if (t[i - 1][j] == 0) {
            r[idx++] = (i - 1) * 10 + j;
            t[i - 1][j] = 1;
            i--;
            return 1;
        }
        return -1;
    }

    private static int right() {
        if (checkDie(i * 10 + j + 1)) {
            return 0;
        }
        if (t[i][j + 1] == 0) {
            r[idx++] = i * 10 + j + 1;
            t[i][j + 1] = 1;
            j++;
            return 1;
        }
        return -1;
    }

    private static int down() {
        if (checkDie((i + 1) * 10 + j)) {
            return 0;
        }

        if (t[i + 1][j] == 0) {
            r[idx++] = (i + 1) * 10 + j;
            t[i + 1][j] = 1;
            i++;
            return 1;
        }
        return -1;
    }

    private static int left() {
        if (checkDie(i * 10 + j - 1)) {
            return 0;
        }
        if (t[i][j - 1] == 0) {
            r[idx++] = i * 10 + j - 1;
            t[i][j - 1] = 1;
            j--;
            return 1;
        }
        return -1;
    }

    private static boolean checkDie(int next) {
        return die.contains(getPath(idx) + next + "/");
    }

    private static boolean back() {

        String p = getPath(idx);
        if (!die.contains(p))
            die.add(getPath(idx));

        if (idx > 0) {
            idx--;
            if (t[r[idx] / 10][r[idx] % 10] == 1) {
                t[r[idx] / 10][r[idx] % 10] = 0;
            }

        }

        if (idx > 0) {
            i = r[idx - 1] / 10;
            j = r[idx - 1] % 10;
            return false;
        }

        return true;
    }

    private static String getPath(int pos) {
        StringBuilder s = new StringBuilder();
        for (int x = 0; x < pos; x++) {
            s.append(r[x]).append("/");
        }
        return s.toString();
    }


    private static String getPos(int v) {
        for (int x = 1; x <= 25; x++) {
            if (r[x - 1] == v) return "" + (x + 10);
        }
        return "  ";
    }

    private static void echo1() {
        System.out.println();
        System.out.println((bb++) + ". -----------");
        for (int x = 1; x <= 5; x++) {
            for (int y = 1; y <= 5; y++) {
                System.out.print(getPos(10 * x + y) + " ");
            }

            System.out.println();
        }

    }

}

 

 

 如果差一个圈的有1064个解法，展示一部分：

1. -----------
11    15 16 17 
12 13 14    18 
31 30 25 24 19 
32 29 26 23 20 
33 28 27 22 21 

2. -----------
11    15 16 17 
12 13 14    18 
31 32 25 24 19 
30 33 26 23 20 
29 28 27 22 21 

3. -----------
11    15 16 17 
12 13 14    18 
33 32 25 24 19 
30 31 26 23 20 
29 28 27 22 21 

4. -----------
11    15 16 17 
12 13 14    18 
29 28 25 24 19 
30 27 26 23 20 
31 32 33 22 21 

 

评论

2 楼 openxtiger 2015-09-21  

太强了，一点都看不懂

1 楼 metaphy 2015-09-15  

无解. 定义n(A)为从A点发出的射线数, 若有解,则

n(0,0) = 1, 必为始点或终点
n(0,1) = 3, 必为始点或终点
n(1,1) = 3, 必为始点或终点

导致矛盾