根据经纬度和半径计算经纬度范围 (转)

一共有两个方法:

第一个是 根据提供的经度和纬度、以及半径，取得此半径内的最大最小经纬度

第二个就是根据提供的两个经纬度计算距离

public class LatLonUtil {   
       
    private static final double PI = 3.14159265;   
    private static final double EARTH_RADIUS = 6378137;   
    private static final double RAD = Math.PI / 180.0;   
  
    //@see http://snipperize.todayclose.com/snippet/php/SQL-Query-to-Find-All-Retailers-Within-a-Given-Radius-of-a-Latitude-and-Longitude--65095/    
    //The circumference of the earth is 24,901 miles.   
    //24,901/360 = 69.17 miles / degree     
    /**  
     * @param raidus 单位米  
     * return minLat,minLng,maxLat,maxLng  
     */  
    public static double[] getAround(double lat,double lon,int raidus){   
           
        Double latitude = lat;   
        Double longitude = lon;   
           
        Double degree = (24901*1609)/360.0;   
        double raidusMile = raidus;   
           
        Double dpmLat = 1/degree;   
        Double radiusLat = dpmLat*raidusMile;   
        Double minLat = latitude - radiusLat;   
        Double maxLat = latitude + radiusLat;   
           
        Double mpdLng = degree*Math.cos(latitude * (PI/180));   
        Double dpmLng = 1 / mpdLng;   
        Double radiusLng = dpmLng*raidusMile;   
        Double minLng = longitude - radiusLng;   
        Double maxLng = longitude + radiusLng;   
        //System.out.println("["+minLat+","+minLng+","+maxLat+","+maxLng+"]");   
        return new double[]{minLat,minLng,maxLat,maxLng};   
    }   
       
    /**  
     * 根据两点间经纬度坐标（double值），计算两点间距离，单位为米  
     * @param lng1  
     * @param lat1  
     * @param lng2  
     * @param lat2  
     * @return  
     */  
    public static double getDistance(double lng1, double lat1, double lng2, double lat2)   
   {   
      double radLat1 = lat1*RAD;   
       double radLat2 = lat2*RAD;   
       double a = radLat1 - radLat2;   
       double b = (lng1 - lng2)*RAD;   
       double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a/2),2) +   
        Math.cos(radLat1)*Math.cos(radLat2)*Math.pow(Math.sin(b/2),2)));   
       s = s * EARTH_RADIUS;   
       s = Math.round(s * 10000) / 10000;   
       return s;   
    }   
       
    public static void main(String[] args){   
        Double lat1 = 34.264648;   
        Double lon1 = 108.952736;   
           
       int radius = 1000;   
        //[34.25566276027792,108.94186385411045,34.27363323972208,108.96360814588955]   
        getAround(lat1,lon1,radius);   
           
        //911717.0   34.264648,108.952736,39.904549,116.407288   
        double dis = getDistance(108.952736,34.264648,116.407288,39.904549);    
        System.out.println(dis);   
    }   
}  

 

原文地址:http://314858770.iteye.com/blog/939834