ZOJ-1251 平均化

1251:很多堆高低不等的砖块，每次移动一个，为了弄成等高，求最少步数。

Sample Input

6
5 2 4 1 7 5
0


Sample Output

Set #1
The minimum number of moves is 5.



简单题。先求平均，凡是大于平均的部分都移走,即得结果。

#include<stdio.h>
#include<iostream>
using namespace std;

int heap[50];
int main()
{
	int n;
	int sum;
	int step;
	int level;
	int count=1;
	while(1)
	{
		cin>>n;
		sum=0;
		step=0;
		if(n==0)
			break;

		for(int i=0;i<n;i++)
		{
			cin>>heap[i];
			sum+=heap[i];
		}

		level = sum/n;
		for(int i=0;i<n;i++)
		{
			if(heap[i]>level)
				step+=heap[i]-level;
		}

		cout<<"Set #"<<count<<endl;
		cout<<"The minimum number of moves is "<<step<<"."<<endl;
		cout<<endl;
		count++;

	}