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最新评论
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likesky3:
看了数据结构书得知并不是迭代和递归的区别,yb君的写法的效果是 ...
Leetcode - Graph Valid Tree -
likesky3:
迭代和递归的区别吧~
Leetcode - Graph Valid Tree -
qb_2008:
还有一种find写法:int find(int p) { i ...
Leetcode - Graph Valid Tree -
qb_2008:
要看懂这些技巧的代码确实比较困难。我是这么看懂的:1. 明白这 ...
Leetcode - Single Num II -
qb_2008:
public int singleNumber2(int[] ...
Leetcode - Single Num II
Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified.
You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad extra spaces ' ' when necessary so that each line has exactly L characters.
Extra spaces between words should be distributed as evenly as possible. If the number of spaces on a line do not divide evenly between words, the empty slots on the left will be assigned more spaces than the slots on the right.
For the last line of text, it should be left justified and no extra space is inserted between words.
For example,
words: ["This", "is", "an", "example", "of", "text", "justification."]
L: 16.
Return the formatted lines as:
[
"This is an",
"example of text",
"justification. "
]
Note: Each word is guaranteed not to exceed L in length.
[分析] 该题算法本身不复杂,考察的是对边界条件的处理。题意把握上主要两点:1)当某行只能放下一个单词时,空格全部放在右边 2)最后一行单词间仅有一个空格,多余空格均放在右边。详细分析参考http://blog.csdn.net/linhuanmars/article/details/24063271
You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad extra spaces ' ' when necessary so that each line has exactly L characters.
Extra spaces between words should be distributed as evenly as possible. If the number of spaces on a line do not divide evenly between words, the empty slots on the left will be assigned more spaces than the slots on the right.
For the last line of text, it should be left justified and no extra space is inserted between words.
For example,
words: ["This", "is", "an", "example", "of", "text", "justification."]
L: 16.
Return the formatted lines as:
[
"This is an",
"example of text",
"justification. "
]
Note: Each word is guaranteed not to exceed L in length.
[分析] 该题算法本身不复杂,考察的是对边界条件的处理。题意把握上主要两点:1)当某行只能放下一个单词时,空格全部放在右边 2)最后一行单词间仅有一个空格,多余空格均放在右边。详细分析参考http://blog.csdn.net/linhuanmars/article/details/24063271
public class Solution { public List<String> fullJustify(String[] words, int maxWidth) { List<String> result = new ArrayList<String>(); if (words == null || words.length == 0 || maxWidth < 0) return result; int count = 0, last = 0; for (int i = 0; i < words.length; i++) { if (count + words[i].length() + (i - last) > maxWidth) { int extraNum = 0, spaceNum = 0; if (i - 1 > last) { spaceNum = (maxWidth - count) / (i - 1 - last); extraNum = (maxWidth - count) % (i - 1 - last); } StringBuilder avgSpaces = new StringBuilder(); while (spaceNum > 0) { avgSpaces.append(" "); spaceNum--; } StringBuilder row = new StringBuilder(); for (int j = last; j < i - 1; j++) { row.append(words[j]); row.append(avgSpaces.toString()); if (extraNum > 0) { row.append(" "); extraNum--; } } row.append(words[i - 1]); for (int j = row.length(); j < maxWidth; j++) { row.append(" "); } result.add(row.toString()); count = 0; last = i; } count += words[i].length(); } // deal with the last row which sometimes not processed int the above loop StringBuilder row = new StringBuilder(); for (int i = last; i < words.length; i++) { row.append(words[i]); if (row.length() < maxWidth) row.append(" "); } while (row.length() < maxWidth) row.append(" "); result.add(row.toString()); return result; } }
发表评论
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Leetcode - Integer to English Words
2015-09-04 20:53 1110[分析] 这题通过率之所以非常低是因为有很多corner ca ... -
Leetcode - Read N Characters Given Read4 II - Call Multiple Times
2015-08-28 09:00 860The API: int read4(char *buf) r ... -
Leetcode - Read N Characters Given Read4
2015-08-27 20:56 698The API: int read4(char *buf) r ... -
Leetcode - One Edit Distance
2015-08-27 20:26 554[分析] 两字符串相同或者长度差异大于等于2都不符合要求,只需 ... -
Leetcode - Isomorphic Strings
2015-08-23 09:51 554[分析] 思路1:维护两个哈希表,char[] map, bo ... -
Leetcode - Group Shifted String
2015-08-22 16:20 1734Given a string, we can "sh ... -
Leetcode - Strobogrammatic Number
2015-08-22 10:48 1101A strobogrammatic number is a n ... -
Leetcode - Valid Number
2015-06-21 10:42 666Validate if a given string is n ... -
Leetcode - Substring with Contentaion of All Words
2015-06-18 10:01 518You are given a string, s, and ... -
Leetcode - Simplify Path
2015-06-17 21:58 433Given an absolute path for a fi ... -
Leetcode - ZigZag Conversion
2015-06-15 21:31 544The string "PAYPALISHIRING ... -
Leetcode - Multiply String
2015-06-15 09:39 688Given two numbers represented a ... -
Leetcode - Minimum Window String
2015-06-14 19:33 587Given a string S and a string T ... -
Leetcode - Longest Substring Without Repeating Characters
2015-06-14 15:34 570Given a string, find the length ... -
Leetcode - Implement strStr()
2015-06-13 19:54 760Implement strStr(). Returns the ... -
Leetcode - Add Binary
2015-06-13 17:34 304Given two binary strings, retu ... -
Leetcode - Compare Version Numbers
2015-06-13 16:36 465Compare two version numbers ver ... -
Leetcode - Shortest Palindrome
2015-06-13 10:55 567Given a string S, you are allow ... -
Leetcode - Longest Palindrome Substring
2015-06-11 09:48 458<div class="iteye-blog- ...
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