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Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k.
给定一个数组判断数组中是否存在两个相同的数,它们之间的差最大为k。我们借助HashMap, key中存放数组的元素nums[i],value中存放对应的下标i。如果遇到相同的key,就对比当前元素的下标i与key中value的值与k的大小,如果i - get(key) 小于等于k就说明存在,返回true。代码入下:
给定一个数组判断数组中是否存在两个相同的数,它们之间的差最大为k。我们借助HashMap, key中存放数组的元素nums[i],value中存放对应的下标i。如果遇到相同的key,就对比当前元素的下标i与key中value的值与k的大小,如果i - get(key) 小于等于k就说明存在,返回true。代码入下:
public class Solution { public boolean containsNearbyDuplicate(int[] nums, int k) { if(nums == null || nums.length < 2) return false; HashMap<Integer, Integer> hm = new HashMap<Integer, Integer>(); for(int i = 0; i < nums.length; i++) { if(hm.containsKey(nums[i])) { if(i - hm.get(nums[i]) <= k) return true; } hm.put(nums[i], i); } return false; } }
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