将给定数组按首字符不同排列

给定一个全有数字组成的字符串数组{'2', '13', '24', '51', '19'}，输出效果是：

13, 19

2, 24

51

主要是利用String类的一些方法实现。

//实现将诸如：{'1', '12', '21', '148', '27', '34'}，按首个字符分行输出的功能:
//13, 19
//2, 24
//51
public class JudgeAndOutput {
	public static void judgeAndDisplay (int[] intArray, int key){
	   String outputString = "";
	   String tempString = "";
	   String keyString = String.valueOf(key);
		
	   for (int i=0; i<intArray.length; i++){
	      tempString = String.valueOf(intArray[i]);
			
	      if (tempString.startsWith(keyString)){
	         outputString += tempString +" ";
	      }
	    }
	   System.out.println("The row with "+ key +" as first is: "+ outputString);
	}
	
	public static void main (String args[]){
	   int[] intArray = new int[100];
		
	   for (int i=1; i<=100; i++){
	      intArray[i-1] = i;
	   }
		
	   for (int key=1; key<10; key++){
	      judgeAndDisplay (intArray, key);
	   }
	}
}

输出结果为：

The row with 1 as first is: 1 10 11 12 13 14 15 16 17 18 19 100 
The row with 2 as first is: 2 20 21 22 23 24 25 26 27 28 29 
The row with 3 as first is: 3 30 31 32 33 34 35 36 37 38 39 
The row with 4 as first is: 4 40 41 42 43 44 45 46 47 48 49 
The row with 5 as first is: 5 50 51 52 53 54 55 56 57 58 59 
The row with 6 as first is: 6 60 61 62 63 64 65 66 67 68 69 
The row with 7 as first is: 7 70 71 72 73 74 75 76 77 78 79 
The row with 8 as first is: 8 80 81 82 83 84 85 86 87 88 89 
The row with 9 as first is: 9 90 91 92 93 94 95 96 97 98 99 

有没有更好的办法呢？