CXF版本3.0.0-milestone1存在BUG

使用CXF的3.0.0-milestone1做签名、加密时发现异常。具体异常堆栈如下：

Exception in thread "main" javax.xml.ws.soap.SOAPFaultException: Can't find bundle for base name org/apache/xml/security/resource/xmlsecurity, locale zh_CN
	at org.apache.cxf.jaxws.JaxWsClientProxy.invoke(JaxWsClientProxy.java:159)
	at sun.proxy.$Proxy44.sayHi(Unknown Source)
	at Main.main(Main.java:11)
Caused by: java.util.MissingResourceException: Can't find bundle for base name org/apache/xml/security/resource/xmlsecurity, locale zh_CN
	at java.util.ResourceBundle.throwMissingResourceException(ResourceBundle.java:1499)
	at java.util.ResourceBundle.getBundleImpl(ResourceBundle.java:1322)
	at java.util.ResourceBundle.getBundle(ResourceBundle.java:724)
	at org.apache.wss4j.common.crypto.WSProviderConfig$4.<init>(WSProviderConfig.java:138)
	at org.apache.wss4j.common.crypto.WSProviderConfig.initializeResourceBundles(WSProviderConfig.java:135)
	at org.apache.wss4j.common.crypto.WSProviderConfig.init(WSProviderConfig.java:69)
	at org.apache.wss4j.dom.WSSConfig.init(WSSConfig.java:387)
	at org.apache.wss4j.dom.WSSConfig.getNewInstance(WSSConfig.java:394)
	at org.apache.cxf.ws.security.wss4j.WSS4JOutInterceptor$WSS4JOutInterceptorInternal.handleMessage(WSS4JOutInterceptor.java:180)
	at org.apache.cxf.ws.security.wss4j.WSS4JOutInterceptor$WSS4JOutInterceptorInternal.handleMessage(WSS4JOutInterceptor.java:140)
	at org.apache.cxf.phase.PhaseInterceptorChain.doIntercept(PhaseInterceptorChain.java:308)
	at org.apache.cxf.endpoint.ClientImpl.doInvoke(ClientImpl.java:502)
	at org.apache.cxf.endpoint.ClientImpl.invoke(ClientImpl.java:411)
	at org.apache.cxf.endpoint.ClientImpl.invoke(ClientImpl.java:314)
	at org.apache.cxf.endpoint.ClientImpl.invoke(ClientImpl.java:267)
	at org.apache.cxf.frontend.ClientProxy.invokeSync(ClientProxy.java:96)
	at org.apache.cxf.jaxws.JaxWsClientProxy.invoke(JaxWsClientProxy.java:137)
	... 2 more

在使用Maven搭建的工程将cxf版本替换为3.0.0解决！！！。

出现问题的根本原因是由于wss4j-ws-security-common-2.0-beta.jar中的WSProviderConfig类initializeResourceBundles方法出现问题：

 private static void initializeResourceBundles() {

        ResourceBundle resourceBundle = new ResourceBundle() {

            private final ResourceBundle wss4jSecResourceBundle = ResourceBundle.getBundle("messages.wss4j_errors");
            private final ResourceBundle xmlSecResourceBundle = ResourceBundle.getBundle(Constants.exceptionMessagesResourceBundleBase);

            @Override
            protected Object handleGetObject(String key) {
                Object value = null;
                try {
                    value = wss4jSecResourceBundle.getObject(key);
                } catch (MissingResourceException e) {
                    try {
                        value = xmlSecResourceBundle.getObject(key);
                    } catch (MissingResourceException ex) { //NOPMD
                        //ignore
                    }
                }
                return value;
            }

            @Override
            public Enumeration<String> getKeys() {
                throw new UnsupportedOperationException("getKeys not supported");
            }
        };
        I18n.init(resourceBundle);
    }

 在2.0.0版本中为：

  public WSS4JResourceBundle() {
        wss4jSecResourceBundle = ResourceBundle.getBundle("messages.wss4j_errors");
        
        ResourceBundle tmpResourceBundle;
        try {
            tmpResourceBundle = 
                ResourceBundle.getBundle(Constants.exceptionMessagesResourceBundleBase,
                        Locale.getDefault(),
                        I18n.class.getClassLoader());
        } catch (MissingResourceException ex) {
            // Using a Locale of which there is no properties file.
            LOG.debug(ex.getMessage());
            // Default to en/US
            tmpResourceBundle = 
                ResourceBundle.getBundle(Constants.exceptionMessagesResourceBundleBase,
                                         new Locale("en", "US"), I18n.class.getClassLoader());
        }
        xmlSecResourceBundle = tmpResourceBundle;
    }

 private final ResourceBundle xmlSecResourceBundle = ResourceBundle.getBundle(Constants.exceptionMessagesResourceBundleBase);会导致找不到资源的异常。

评论

1 楼 ljx_523 2014-07-22