js 获取请求地址中的参数 2

1,通过js如何获取get 请求参数呢?

/***
 * get request query string
 * @returns {{}}
 */
var getQueryParams = function () {
	var i, ilen, strs, keyName, keyValue,
		params = {},
		path = window.location.pathname,
		url = window.location.href;
	if (url.indexOf("?") > -1) {
		var index = url.indexOf("?");
		strs = url.substring(index + 1);
		strs = strs.split("&");
		ilen = strs.length;
		for (i = 0; i < ilen; i++) {
			var indexEqual = strs[i].indexOf('=');
			if (indexEqual == -1) {
				keyName = strs[i];
				keyValue = '';
			} else {
				keyName = strs[i].substring(0, indexEqual);
				keyValue = strs[i].substring(indexEqual + 1) || "";
			}

			if (keyName == "callback") keyValue = decodeURIComponent(keyValue);
			params[keyName] = keyValue;
		}
	}
	return params;
};

 

测试:http://localhost:63342/js_svn/request_queryString.html?username=whuang&age=32&callback=?a=b&bb&1=2

打印:

Object {1: "2", username: "whuang", age: "32", callback: "?a=b", bb: ""}

参考:http://hw1287789687.iteye.com/blog/2234658