Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
confused what "{1,#,2,3}"
means? > read more on how binary tree is serialized on OJ.
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public boolean isValidBST(TreeNode root) { ArrayList<Integer> arrayList = new ArrayList<Integer>(); arrayList.add(null); return solve(root, arrayList); } private boolean solve(TreeNode root, ArrayList<Integer> arrayList) { if (root == null) { return true; } boolean left = solve(root.left, arrayList); if (arrayList.get(arrayList.size()-1) != null && root.val<=arrayList.get(arrayList.size()-1)) { return false; } arrayList.add(root.val); boolean right = solve(root.right, arrayList); return left && right; } }
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