GPS纠偏算法，适用于google,高德体系的地图

/**
* gps纠偏算法，适用于google,高德体系的地图
* @author Administrator
*/ 
public class GpsCorrect { 
    final static double pi = 3.14159265358979324; 
    final static double a = 6378245.0; 
    final static double ee = 0.00669342162296594323; 
 
    public static void transform(double wgLat, double wgLon, double[] latlng) { 
        if (outOfChina(wgLat, wgLon)) { 
            latlng[0] = wgLat; 
            latlng[1] = wgLon; 
            return; 
        } 
        double dLat = transformLat(wgLon - 105.0, wgLat - 35.0); 
        double dLon = transformLon(wgLon - 105.0, wgLat - 35.0); 
        double radLat = wgLat / 180.0 * pi; 
        double magic = Math.sin(radLat); 
        magic = 1 - ee * magic * magic; 
        double sqrtMagic = Math.sqrt(magic); 
        dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi); 
        dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi); 
        latlng[0] = wgLat + dLat; 
        latlng[1] = wgLon + dLon; 
    } 
 
    private static boolean outOfChina(double lat, double lon) { 
        if (lon  137.8347) 
            return true; 
        if (lat  55.8271) 
            return true; 
        return false; 
    } 
 
    private static double transformLat(double x, double y) { 
        double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.sqrt(Math.abs(x)); 
        ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0; 
        ret += (20.0 * Math.sin(y * pi) + 40.0 * Math.sin(y / 3.0 * pi)) * 2.0 / 3.0; 
        ret += (160.0 * Math.sin(y / 12.0 * pi) + 320 * Math.sin(y * pi / 30.0)) * 2.0 / 3.0; 
        return ret; 
    } 
 
    private static double transformLon(double x, double y) { 
        double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.sqrt(Math.abs(x)); 
        ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0; 
        ret += (20.0 * Math.sin(x * pi) + 40.0 * Math.sin(x / 3.0 * pi)) * 2.0 / 3.0; 
        ret += (150.0 * Math.sin(x / 12.0 * pi) + 300.0 * Math.sin(x / 30.0 * pi)) * 2.0 / 3.0; 
        return ret; 
    } 
}


源码下载地址：http://download.csdn.net/detail/junfeng120125/5945349

转自：http://blog.csdn.net/junfeng120125/article/details/9966857