登录/注册后跳回登录/注册前的页面实现方法

网站开发中经常会遇到这样的问题，登录后自动转到了首页或者用户管理首页，这样有时候会让用户觉得很不方便，特别是电子商务类的网站，当用于在浏览产品页面时，需要购买，但是只有登录后的用户才能进入购买页面，所以如果当用户登录后进入的不是他登录前的产品浏览页面，他得去重新找，这是非常不友好的。

可以通过request.getHeader("referer");方式来实现登录/注册后返回进入登录或注册页面前的页面

举例:

java 代码

/**
 * 进入到登录页面
 * @param mapping
 * @param form
 * @param request
 * @param response
 * @return
 */
public  ActionForward loginview(ActionMapping mapping, ActionForm form,
        HttpServletRequest request, HttpServletResponse response) {

     //登录后跳转回进来的页面，如果进来之前的页面是登录和退出，则登录后跳转到首页
    String pagefrom = request.getHeader( "referer" );
     if (pagefrom.indexOf( "method=login" )> 0  || pagefrom.indexOf( "method=logout" )> 0 )
    {
        pagefrom = pagefrom.substring( 0 ,pagefrom.lastIndexOf( "/" )+ 1 );
    }
    request.setAttribute( "pagefrom" , pagefrom);

    saveToken(request);

    User object =  null ;
     try  {
        object = entityClass.newInstance();
    }  catch  (InstantiationException e) {
        log.error(e);
    }  catch  (IllegalAccessException e) {
        log.error(e);
    }
    initForm(form, request, object);
     return  mapping.findForward(LOGINVIEW);
}

 

在登录页面中设置hidden元素：

登录页面部分代码

< html:form   action = "/userm.do"   focus = "loginname"   styleClass = "u_login_form"   onsubmit = "return validateUserForm(this)" >
                 < input   type = "hidden"   name = "method"   value = "login" />
                 < input   type = "hidden"   name = "pagefrom"   value = "${ pagefrom }" />
                 < input   type = "hidden"   name = "name"   value = "name" />
                 < input   type = "hidden"   name = "mail"   value = "[e-mail]" />
                 < div   class = "l" > < img   src = "${css}/images/login_icon_01.gif"   /> div >
                 < div   class = "l" >
                     < html:text   property = "loginname"   styleClass = "text" /> < br   />
                     < html:password   property = "password"   styleClass = "text" /> < br   />
                     < %@ include  file = "/commons/messages.jsp"  % >
                 div >
                 < div   class = "l" > < html:img   src = "${css}/images/login_icon_02.gif"   onclick = "if(validateUserForm(document.userForm)) document.userForm.submit();" /> div >
                 < div   class = "c" > div >
             html:form >
             < html:javascript   formName = "userForm"   staticJavascript = "false"   dynamicJavascript = "true"   cdata = "false" />
             < script   type = "text/javascript"   src = "${ctx}/scripts/validator.jsp" > script >

 

根据登录页面中的pagefrom元素的值，在登录成功后跳转到该值对应的页面

登录代码：

java 代码

     /**
     * 登录
     * @param mapping
     * @param form
     * @param request
     * @param response
     * @return
     */
     public  ActionForward login(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response) {
        String pagefrom = request.getParameter( "pagefrom" );
        request.setAttribute( "pagefrom" , pagefrom);

         if  (isCancelled(request))
             return  list(mapping, form, request, response);
         if  (!isTokenValid(request)){
            saveDirectlyError(request,  "重复提交" );
             return  mapping.findForward(LOGINVIEW);
        }
//      resetToken(request);

         // run validation rules on this form
        ActionMessages errors = form.validate(mapping, request);
         if  (!errors.isEmpty()) {
            saveErrors(request, errors);
            refrenceData(request);
             return  mapping.findForward(LOGINVIEW);
        }



        User object = doNewEntity(form, request);
        initEntity(form, request, object);

        User user = userManagerCommon.checkPassword(object.getLoginname(), object.getPassword());
         if ( null ==user)
        {
            errors.add( "password" , new  ActionMessage( "user.missing" ,object.getPassword()));
            saveErrors(request, errors);
             return  mapping.findForward(LOGINVIEW);
        }

        SessionUser.saveSession(request,user);


         try  {
            response.sendRedirect(pagefrom);
             return   null ;
        }  catch  (IOException e) {
            e.printStackTrace();
        }

         return  mapping.findForward(INDEX);
    }

 

第48行的代码就实现了跳转。