Shell Test Issue --[: too many arguments

Today, I'm going to write small shell program to verify the demo servers if alive.  

This is the script:

 

#!/bin/sh

echo "Check Servers status startup...."

MAIL_TITLE="OSL OO DEMO SERVERS Check Failed!"

VM03="oardc-vm03.cn.oracle.com"

FOUND=`ping $VM03 -c 2 | grep '2 received,'`

if [ -n $FOUND ];
then
	echo $VM03' is OK!' | mailx -s "Test OK" [e-mail]
else
 echo $VM03' is Failed!' | mailx -s "$MAIL_TITLE" [e-mail]
fi

echo "Check Servers status done. check your email"

 

 When I run the script in command line, I got the error message:

 

Check Servers status startup....

./test.sh: line 11: [: too many arguments

 Check the line 11:

 

if [ -n $FOUND ];

 

 Why it will cause the problem?

 

 That is the reason:

 when I print the variable:

 

[root@xxxadmin]# echo $FOUND
2 packets transmitted, 2 received, 0% packet loss, time 1000ms

 convert this variable to the expression: if [ -n $FOUND ];

 

 it will be: if [ -n 2 packets transmitted, 2 received, 0% packet loss, time 1000ms ] 

 if you run the command:

 

 

[root@xxxadmin]# [ -n 2 packets transmitted, 2 received, 0% packet loss, time 1000ms ]
-bash: [: too many arguments

 So we should wrap the variable with "

 

 

if [ -n "$FOUND" ];

 Notice the ".

 

That will work well.

 

this is the final version:

 

 

#!/bin/sh

echo "Check Servers status startup...."

MAIL_TITLE="OSL OO DEMO SERVERS Check Failed!"

VM03="oardc-vm03.cn.oracle.com"

FOUND=`ping $VM03 -c 2 | grep '2 received,'`

if [ -n "$FOUND" ];
then
	echo $VM03' is OK!' | mailx -s "Test OK" [e-mail]
else
 echo $VM03' is Failed!' | mailx -s "$MAIL_TITLE" [e-mail]
fi

echo "Check Servers status done. check your email"