webwork in spring

本文主要讲解webwork与spring的集成．

有人说有了webwork就没有必要和spring集成．

也有人说webwork和spring集成起来功能更加强大．

本人同意上述两个观点，本文觉得webwork没有必须要和spring集成，当然我这里仅指springMVC，webwork本身就是一个很好的MVC实现．而webwork可以和spring除SpringMVC以外其的组件集成，像spring的持久层组件．更多的本人也不敢发表言论，大家如果感兴趣可以到网上找找相关的资料．

提示：为了减少视频的录制时间，减少上传文件的空间．本文也是在上几个视频的基础上进行改动．所以在阅读本文之前请先参考上几个视频．可以在本博客上直接下载，webwork国际化这节．<o:p></o:p>

Webwork集成spring

1． 修改 web.xml，为 Web 应用增加相应的 Spring ContextLoaderListener <o:p></o:p>

xml 代码

xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
    <servlet>
        <servlet-name>webwork<!---->servlet-name>
        <servlet-class>
            com.opensymphony.webwork.dispatcher.ServletDispatcher
        <!---->servlet-class>
    <!---->servlet>
    <servlet-mapping>
        <servlet-name>webwork<!---->servlet-name>
        <url-pattern>*.action<!---->url-pattern>
    <!---->servlet-mapping>
    <listener>
        <listener-class>
            org.springframework.web.context.ContextLoaderListener
        <!---->listener-class>
    <!---->listener>
<!---->web-app>

java 代码

package com.lyx.service;
import com.lyx.bo.User;

public interface IUserService {
    public boolean isValidUser(User user);
    }

}

java 代码

package com.lyx.service;
import com.lyx.bo.User;

public class UserService implements IUserService {

    public boolean isValidUser(User user) {
        if (user.getUserName().equals("lyx") && user.getUserPwd().equals("lyx"))
            return true;
        else
            return false;
    }
}

4.修改xwork.xml配置文件<o:p></o:p>

xml 代码

>
<xwork>
<include file="webwork-default.xml" />
    <package name="action" extends="webwork-default">
        <action name="login" class="login">
            <!---->
            <result name="success" type="dispatcher">
                <param name="location">/success.jsp<!---->param>
            <!---->result>
            <!---->
            <result name="error" type="dispatcher">
                <param name="location">/error.jsp<!---->param>
            <!---->result>
            <result name="input" type="dispatcher">
                <param name="location">/index.jsp<!---->param>
            <!---->result>

            <interceptor-ref name="model-driven" />
            <interceptor-ref name="params" />
            <interceptor-ref name="validationWorkflowStack" />
        <!---->action>
    <!---->package>
<!---->xwork>

   5) 添加 spring 框架到项目中

   修改 applicationContext.xml 文件，加入 UserServiceImpl 的配置信息<o:p></o:p>

xml 代码

xml version="1.0" encoding="UTF-8"?>
>

<beans>
    <bean id="userService" class="com.lyx.service.UserService" singleton="false"/>
    <bean id="login" class="com.lyx.web.action.LoginAction" singleton="false" >
        <property name="userService">
            <ref bean="userService"/>
        <!---->property>
    <!---->bean>
<!---->beans>

注意：这里的红色字体login一定要和xwork配置文件中的login一样．<o:p></o:p>

   6) 修改 Action <o:p></o:p>

java 代码

   LoginAction.java
package com.lyx.web.action;
import com.opensymphony.xwork.Action;
import com.opensymphony.xwork.ActionSupport;
import com.opensymphony.xwork.ModelDriven;
import com.test.services.IUserService;
public class LoginAction extends ActionSupport implements Action,ModelDriven  {
    private User user = new User();
    private IUserService userService;
    public User getUser() {
        return user;
    }
    public String execute() throws Exception {
        if (userService.isValidUser(user))
            return this.SUCCESS;
        else
            return this.ERROR;
    }
    public Object getModel() {
        return user;
    }

    public void setUserService(IUserService userService) {
        this.userService = userService;
    }
}

<o:p></o:p>

评论

1 楼 nbspnbsp 2007-06-13  

Thank you!!