Java web页面form提交重定向sendRedirect到web页面

Java web实现jsp页面的form表单提交sendRedirect到jsp页面

1. 创建一个用于提交的jsp页面

myForward.jsp

<form action="MyForwardServlet">
     username:<input type="text" name="username">
     <input type="submit" value="submit"/>
</form>

2. 创建处理请求的servlet，使用重定向sendRedirect

MyForwardServlet.java

package com.andrew.servlet;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class MyForwardServlet extends HttpServlet {
    @Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        String username = request.getParameter("username");
        request.setAttribute("username", username);
        response.sendRedirect("myResult.jsp");
    }
}

3. 在web.xml文件中配置servlet

web.xml

<servlet>
    <servlet-name>MyForwardServlet</servlet-name>
    <servlet-class>com.andrew.servlet.MyForwardServlet</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>MyForwardServlet</servlet-name>
    <url-pattern>/MyForwardServlet</url-pattern>
</servlet-mapping>

4. 创建一个用于跳转的jsp页面

myResult.jsp

username:<%= request.getParameter("username") %><br/>

5. 启动tomcat执行页面提交

username:null