getJSON函数无反应

使用JSON时在页面上的返回值一定要是json格式的数据，例如一个 Map  返回成 Json格式{“result”,true}，如果只是返回true ，jquery的getJSON函数不报任何错误，而且浏览器没有任何反应，javaranch上有一位仁兄也碰到同样的问题：

 

 

 

Josh Nathanson	View profile	More options Nov 19 2007, 3:22 pm

From: "Josh Nathanson" <[e-mail]>

Date: Mon, 19 Nov 2007 12:22:47 -0800

Local: Mon, Nov 19 2007 3:22 pm

Subject: Re: [jQuery] $.getJSON() problem

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Usually this means that your JSON data has an error in the formatting
somewhere - perhaps a missing or extra comma.  If JSON data cannot be
evaluated successfully, it fails silently.

-- Josh

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----- Original Message -----
From: "Aljosa Mohorovic" <[e-mail]>
To: "jQuery (English)" <[e-mail]>
Sent: Monday, November 19, 2007 5:25 AM
Subject: [jQuery] $.getJSON() problem

> i have a problem with $.getJSON(), nothing is logged in firebug
> console although i can see that correct data is returned in response
> (in firebug) for code:

> $.getJSON(url, function(data){
>    console.log(data);
> });
> <<<

> same code, but using $.get instead $.getJSON works as expected:

> $.get(url, function(data){
>    console.log(data);
> });
> <<<

> sometimes it works, but  i can't find where it breaks. also, firebug
> doesn't report any errors.
> any ideas or similar situations?

> Aljosa 

 

正确的返回方法（先倒入 import org.stringtree.json.JSONWriter;）：

 

//If I understand you correctly, using Stringtree JSON it should be as simple as:

1.	JSONWriter jsonWriter = new JSONWriter();  
2.	Map values = new LinkedHashMap();  
3.	   
4.	// I assume you can get your option values from somewhere   
5.	// the following will presumably actually be a loop ...  
6.	values.put("Alaska", "AK");  
7.	values.put("Arizona", "AZ");  
8.	...  
9.	String json = jsonWriter.write(values);  


//This should result in a valid JSON string such as:

1.	{'Alaska':'AZ','Arizona':'AZ'}  

 

客户端使用http://www.JSON.org/json2.js来解析。

 

 

参考：http://cn-arthurs.iteye.com/blog/335549

 http://blog.csdn.net/yzh_510/archive/2009/01/14/3776925.aspx