http://buptdavid.blog.51cto.com/745925/157509
这个问题一般出现在一对多的情况下,解决的方法有两种
1、设置lazy=false
如果是用annotation,则配置如下
@OneToMany(
targetEntity = CourseAuthorizationItem.class,
cascade = {CascadeType.PERSIST, CascadeType.MERGE},
mappedBy = "course", fetch=FetchType.EAGER
)
将fetch类型设置成直接获取
2、就是使用filter,过滤所有的链接
如果在使用filter的时候,要配置事务处理,否则会导致session处于只读状态而不能做修改、删除的动作
<web-app>
<filter>
<filter-name>hibernateFilter</filter-name>
<filter-class>
org.springframework.orm.hibernate.support.OpenSessionInViewFilter
</filter-class>
</filter>
<filter-mapping>
<filter-name>hibernateFilter</filter-name>
<url-pattern>*.do</url-pattern>
</filter-mapping>
</web-app>
failed to lazily initialize a collection of role: XXXXXX, no session or session was closed
例如:failed to lazily initialize a collection of role: com.gtc.wzgl.model.User.roles, no session or session was closed
这个异常大致意思是说在多对一的时候(并且lazy="false"),对象的实例失败,多数出现的情况有
1、粗心造成
实例对象类名写错之类的
2、逻辑错误
如之前就已经传递过来一个实体对象,然后调用实体对象的方法时牵涉到1对多的情况,但此时SESSION已经关闭,所以根本无法进行一对多的操作。
3、设计到跨度的问题:
这样打比方有多个实体对象,他们直接或则间接的有关联。比如有4个实体,分别是广告信息、广告、广告问答题、广告商:他们之间的关系为:
广告商 1:n 广告
广告 1:n 广告问答题
广告商 1:n 广告商信息
大家可以看到广告和广告商信息是没有直接关系的。但我要添加广告的时候我就必须将广告商的实体做为条件。那么这么一来广告商信息可能间接的就必须用上。下面看我的操作:
ad(广告),subject(题目)
Ad ad = new Ad();
ad.setAdProd(adform.getAdProd());
ad.setIndustry(industry);
ad.setAdPicture(pagefile.getFileName());
ad.setAdFlack(adform.getAdFlack());
ad.setAdDv(dvfile.getFileName());
ad.setAdContent(adform.getAdContent());
ad.setGray(gray);
ad.setAdDate(new Date());
ad.setOnlinetime(new Long(0));
//以上为广告的基本信息填写,而重要的是看下面一句,在这里我的思路是subjectFormList是一个动态提交的表单,里面有若干个广告问答题。我将这些问答题变为一个Set,然后作为ad的一个属性。
Set<Subject> subjectset=getSubjectSet(subjectFormList,ad);
ad.setSubjects(subjectset);
//然后提交,makePersistent是一个封装的方法,用途就是save()啦。addao是一个DAO,里面有ADUS。
addao.makePersistent(ad);
表面上看来很符合逻辑,只要我们在ad的映射里面加上对subject的级联更新就可以完成这项操作。但实际上会发生我们意想不到的问题,来让我们看一下getSubjectSet()的内容:
public Set getSubjectSet(List<SubjectForm> subjectlist,Ad ad)
{
Set<Subject> set=new HashSet<Subject>(0);
Subject subject;
for(Iterator<SubjectForm> it=subjectlist.iterator();it.hasNext();)
{
subject=new Subject();
SubjectForm sf=it.next();
subject.setSuContent(sf.getSucontent());
subject.setSuOption(sf.getSuoption());
subject.setSuResult(Arrays.deepToString(sf.getSuresult()));
subject.setSuType(String.valueOf(sf.getSutype()));
subject.setAd(ad);
set.add(subject);
}
return set;
}
我们在这个方法上设一个断点然后跟踪,之后你会发现断点在set.add(subject)只后就会出failed to lazily initialize a collection of role: XXXXXXXX no session or session was closed这个异常,并且这个异常还是出在了广告商的广告信息上 gray.messages。是不是很不可理解?这也是Hibernate的懒汉机制问题。没有任何一样技术是完美的。那我们该怎么处理这样的问题。有很多人以为我们在广告商对广告商信息的隐射上加lazy="false"这样在对gray操作会对messages进行关联,并查询时提出数据。但你会发现改完之后会出现org.hibernate.LazyInitializationException: illegal access to loading collection这个异常。并切lazy="false"是我们不推荐的一种方法。他会降低你的查询效率。
对于这样的情况最好的解决办法就是不要偷懒,对一个实体进行操作的时候就该用那个实体的DAO,即应该有2句HQL。如下把getSubjectSet()改一改:
public void getSubjectSet(List<SubjectForm> subjectlist,Ad ad)
{
Set<Subject> set=new HashSet<Subject>(0);
SubjectDAO subjectdao=DAOFactory.getDao(SubjectDAO.class);
for(Iterator<SubjectForm> it=subjectlist.iterator();it.hasNext();)
{
Subject subject=new Subject();
SubjectForm sf=it.next();
subject.setSuContent(sf.getSucontent());
subject.setSuOption(sf.getSuoption());
subject.setSuResult(Arrays.deepToString(sf.getSuresult()));
subject.setSuType(String.valueOf(sf.getSutype()));
subject.setAd(ad);
subjectdao.makePersistent(subject);
//set.add(subject);
}
}//遍历出所有subject一个个的往数据库里加。这样便不会出问题了。
1、OpenSessionInView模式:
以下有2种方法,第1种是结合SPRING,第2种是采用了拦截器
Spring+Hibernate中, 集合映射如果使用lazy="true", 当PO传到View层时, 出现未初始化session已关闭的错误,只能在dao先初始化
parent.getChilds().size();
Spring提供Open Session In View来解决这个问题, 有两种方式
1. Interceptor
<!--</span><span style="COLOR: rgb(0,128,0)"> =========== OpenSession In View pattern ==============</span><span style="COLOR: rgb(0,128,0)">-->
<bean id="openSessionInViewInterceptor"
class="org.springframework.orm.hibernate3.support.OpenSessionInViewInterceptor">
<property name="sessionFactory" ref="sessionFactory"/>
</bean>
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="interceptors" ref="openSessionInViewInterceptor"/>
<property name="mappings">
<props>
......
</props>
</property>
</bean>
2. Filter
<web-app>
<filter>
<filter-name>hibernateFilter</filter-name>
<filter-class>
org.springframework.orm.hibernate.support.OpenSessionInViewFilter
</filter-class>
</filter>
<filter-mapping>
<filter-name>hibernateFilter</filter-name>
<url-pattern>*.do</url-pattern>
</filter-mapping>
</web-app>
第2种解决方法:
Hibernate.initialize()强制加载关联对象
今天又碰到错误
failed to lazily initialize a collection of role: no session or session was closed
试验了一下发现了几个解决方法:
1、是把对应一对多的那两个列lazy=true改为lazy=false即可
2、对于查询中如果用的是xxx.load(class,id)则改为xxx,get(class,id)
3在web.xml文件中加入
<filter>
<filter-name>hibernateFilter</filter-name>
<filter-class>org.springframework.orm.hibernate3.support.OpenSessionInViewFilter</filter-class>
<init-param>
<param-name>singleSession</param-name>
<param-value>false</param-value>
</init-param>
<!--这个-- <init-param>一定要加不然很可能会报错:org.springframework.dao.InvalidDataAccessApiUsageException: Write operations are not allowed in read-only mode (FlushMode.NEVER) - turn your Session into FlushMode.AUTO or remove 'readOnly' marker from transaction definition
>
</filter>
<filter-mapping>
<filter-name>hibernateFilter</filter-name>
<url-pattern>*.mmg</url-pattern>
</filter-mapping>
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