C程序员如何申请加薪？呵呵

如果老板会编译程序的话，发下面这段代码给他：

#include <stdio.h>
int main() {
    int a,b,c;
    for (c=0,b=0;a="BCCB{BC@BDBBCEFCCBDECFDDBBCBBBC@BBABABBBCBDBBBBBBBCBBBCBBBBACBABCBC@BBBDBBCBDBBBBBBBCBBBCBBBAAECI@BBCCCEEBBBBBCECBCBCDDBEBC@}BK@"[b++];)
        for(; a-- > 64 ; )
            putchar ( ++c==74 ? c=0,10 : b&1?32:36);
    return 0;
}

执行结果：


怎么样？主意不错吧？祝你成功！

上面程序的数字74是换行符所在的位置，其它数字找一个ASCII码表对照着看就明白了。弄懂之后，就可以随心所欲地实现其它显示效果了，关键是上面的字符串是怎样产生的呢？请看下面的程序，注释足够清晰了，不解释：

#include <stdio.h>
int main() {
    char signature[6][128];
    strcpy(signature[0], "$$   $$$  $$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$  $$");
    strcpy(signature[1], "$$    $$  $$$     $$$$$$   $$$  $$$$     $$$      $$$$    $$  $$$  $$  $$");
    strcpy(signature[2], "$$  $  $  $$  $$$  $$$$  $$  $$  $$  $$$  $$  $$$  $$  $$ $$$  $  $$$  $$");
    strcpy(signature[3], "$$  $$    $$  $$$  $$$$  $$  $$  $$  $$$  $$  $$$  $$  $ $$$$$   $$$$$$$$");
    strcpy(signature[4], "$$  $$$   $$$     $$$$$  $$  $$  $$$     $$$  $$$  $$$    $$$$  $$$$$  $$");
    strcpy(signature[5], "$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$  $$$$$$$$$$");
    char output[256];
    memset(output, 0, sizeof(output));
    int i, j = 0;
    for (i = 0; i < 6; i++) {
        char *p = signature[i];
        while ( p ) {
            char *p1 = strchr(p, ' ');
            if ( p1 ) {
                output[j++] = p1 - p + 64;
                // assume every line ends with $, p always not null
                p = strchr(p1, '$');
                output[j++] = p - p1 + 64;
            }
            else {
                // +1 for the newline character will "eat" one character
                output[j++] = strlen(p) + 64 + 1;
                output[j++] = 64;
                // end of current line, switch to next line
                p = NULL;
            }
        }
    }
    printf("%s\n", output);
    return 0;
}

受ASCII码取值范围的限制，这种小伎俩不适宜显示太复杂的效果