短信分割算法 转

  /**
     * 以给定的<code> LENGTH </code>分割短信内容，返回分割后的字符串数组<br>
     * 以下是返回内容示例：
     *
     * <pre>
     * sSMS = “abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyz”;
     * 1. 分割后的短信个数 < 10
     * LENGTH = 10;
     * (1/6)abcdefghij
     * (2/6)klmnopqrst
     * (3/6)uvwxyzabcd
     * (4/6)efghijklmn
     * (5/6)opqrstuvwx
     * (6/6)yz = 7
     *
     * 2. 分割后的短信个数 >= 10
     * LENGTH = 5;
     * (1/15)abcd
     * (2/15)efgh
     * (3/15)ijkl
     * ......
     * (13/15)tuv
     * (14/15)wxy
     * (15/15)z
     * </pre>
     *
     * @param sSMS
     *            短信内容
     * @param LENGTH
     *            每条短信的长度
     * @return 一组短信内容
     */
    public static String[] smsSplit(String sSMS, final int LENGTH) {
       int iContentLength = sSMS.trim().length();
       if (LENGTH >= iContentLength) {
           // 短信内容的长度小于等于LENGTH，不用分割直接返回
           return new String[] { sSMS };
       }

       final int iSMS_Num_9 = 9; // 分割9条短信
       int iSum = LENGTH * iSMS_Num_9; // 短信条数等于9的总长度，
       int iLength = 0;
       if (iContentLength > iSum) {
           // 源短信的长度大于iSum，表示源短信可以被分割的数量超过10条
           iLength = LENGTH - 1;
           iSum = iLength * iSMS_Num_9;
       } else if (iContentLength < iSum) {
           // 源短信的长度小于iSum，表示源短信可以被分割的数量小于等于9条
           iLength = LENGTH;
           iSum = iContentLength;
       }

       // 短信个数小于10
       String sSMS9 = sSMS.trim().substring(0, iSum);
       String[] aSMS9 = smsSplitByLength(sSMS9, iLength);

       if (iContentLength == iSum) {
           List<String> oList = new ArrayList<String>();
           String sTemp;
           final int iSMSNum = aSMS9.length;
           for (int i = 0; i < aSMS9.length; i++) {
              sTemp = "(" + (i + 1) + "/" + iSMSNum + ")" + aSMS9[i];
              oList.add(sTemp);
           }
           String[] aSMS = oList.toArray(new String[0]);
           return aSMS;
       }

       String sTemp1 = aSMS9[aSMS9.length - 1];
       String sTemp2 = aSMS9[aSMS9.length - 2];

       String sSMS10 = null;
       String[] aSMS10 = null;
       if (sTemp1.length() != sTemp2.length()) {
           String[] aTemp = aSMS9;
           aSMS9 = new String[aTemp.length - 1];
           System.arraycopy(aTemp, 0, aSMS9, 0, aTemp.length - 1);
           sSMS10 = sTemp1 + sSMS.trim().substring(iSum);
           aSMS10 = smsSplitByLength(sSMS10, iLength - 1);
       } else {
           sSMS10 = sSMS.trim().substring(iSum);
           aSMS10 = smsSplitByLength(sSMS10, iLength - 1);
       }

       List<String> oList = new ArrayList<String>();
       String sTemp;
       final int iSMSNum = aSMS9.length + aSMS10.length;
       for (int i = 0; i < aSMS9.length; i++) {
           sTemp = "(" + (i + 1) + "/" + iSMSNum + ")" + aSMS9[i];
           oList.add(sTemp);
       }
       for (int i = 0; i < (aSMS10.length); i++) {
           sTemp = "(" + (i + 10) + "/" + iSMSNum + ")" + aSMS10[i];
           oList.add(sTemp);
       }
       String[] aSMS = oList.toArray(new String[0]);
       return aSMS;
    }

    /**
     * 以给定的<code> LENGTH </code>分割短信内容，返回分割后的字符串数组<br>
     * <b>注意：返回数组中的最后一个元素的字符串长度不一定等于<code> LENGTH </code>，<br>
     * 即不考虑<code> sSMS.length % LENGTH != 0 </code></b>
     *
     * @param sSMS
     *            短信内容
     * @param LENGTH
     *            每条短信的长度
     * @return 一组短信内容
     */
    private static String[] smsSplitByLength(String sSMS, final int LENGTH) {
       int iContentLength = sSMS.trim().length();
       String sTemp;
       int x = 0;
       int y = 0;
       List<String> l = new ArrayList<String>();
       while (true) {
           y = x + LENGTH;
           if (y > iContentLength)
              y = iContentLength;
           sTemp = sSMS.substring(x, y);
           l.add(sTemp);
           x = y;
           if (x == iContentLength)
              break;
       }
       return l.toArray(new String[0]);
    }