程序设计-01

1.写一个函数，讲数字转换成中文大写形式，如输入123456，转换成拾贰万叁千肆佰伍拾陆。

代码转自：http://blog.csdn.net/netfalcon/archive/2004/03/09/21645.aspx

代码如下：

package cn.myTest;

import java.lang.String;

import java.lang.Math;

public class Change {
	// 调试时用main函数
	public static void main(String args[]) {
		Change mon = new Change();
		System.out.println(mon.NumToRMBStr(100000001.05));
					
	}

	String HanDigiStr[] = new String[] { "零", "壹", "贰", "叁", "肆", "伍", "陆",
			"柒", "捌", "玖" };

	String HanDiviStr[] = new String[] { "", "拾", "佰", "仟", "万", "拾", "佰", "仟",
			"亿", "拾", "佰", "仟", "万", "拾", "佰", "仟", "亿", "拾", "佰", "仟", "万",
			"拾", "佰", "仟" };

	String PositiveIntegerToHanStr(String NumStr) { // 输入字符串必须正整数，只允许前导空格(必须右对齐)，不宜有前导零
		String RMBStr = "";
		boolean lastzero = false;
		boolean hasvalue = false; // 亿、万进位前有数值标记
		int len, n;
		len = NumStr.length();
		if (len > 15)
			return "数值过大!";
		for (int i = len - 1; i >= 0; i--) {
			if (NumStr.charAt(len - i - 1) == ' ')
				continue;
			n = NumStr.charAt(len - i - 1) - '0';
			if (n < 0 || n > 9)
				return "输入含非数字字符!";

			if (n != 0) {
				if (lastzero)
					RMBStr += HanDigiStr[0]; // 若干零后若跟非零值，只显示一个零
				// 除了亿万前的零不带到后面
				// if( !( n==1 && (i%4)==1 && (lastzero || i==len-1) ) ) //
				// 如十进位前有零也不发壹音用此行
				if (!(n == 1 && (i % 4) == 1 && i == len - 1)) // 十进位处于第一位不发壹音
					RMBStr += HanDigiStr[n];
				RMBStr += HanDiviStr[i]; // 非零值后加进位，个位为空
				hasvalue = true; // 置万进位前有值标记

			} else {
				if ((i % 8) == 0 || ((i % 8) == 4 && hasvalue)) // 亿万之间必须有非零值方显示万
					RMBStr += HanDiviStr[i]; // “亿”或“万”
			}
			if (i % 8 == 0)
				hasvalue = false; // 万进位前有值标记逢亿复位
			lastzero = (n == 0) && (i % 4 != 0);
		}

		if (RMBStr.length() == 0)
			return HanDigiStr[0]; // 输入空字符或"0"，返回"零"
		return RMBStr;
	}

	String NumToRMBStr(double val) {
		String SignStr = "";
		String TailStr = "";
		long fraction, integer;
		int jiao, fen;

		if (val < 0) {
			val = -val;
			SignStr = "负";
		}
		if (val > 99999999999999.999 || val < -99999999999999.999)
			return "数值位数过大!";
		// 四舍五入到分
		long temp = Math.round(val * 100);
		integer = temp / 100;
		fraction = temp % 100;
		jiao = (int) fraction / 10;
		fen = (int) fraction % 10;
		if (jiao == 0 && fen == 0) {
			TailStr = "整";
		} else {
			TailStr = HanDigiStr[jiao];
			if (jiao != 0)
				TailStr += "角";
			if (integer == 0 && jiao == 0) // 零元后不写零几分
				TailStr = "";
			if (fen != 0)
				TailStr += HanDigiStr[fen] + "分";
		}

		// 下一行可用于非正规金融场合，0.03只显示“叁分”而不是“零元叁分”
		// if( !integer ) return SignStr+TailStr;

		return "￥" + SignStr + PositiveIntegerToHanStr(String.valueOf(integer))
				+ "元" + TailStr;
	}

}// END public class money

2.讲括号进行匹配，括号不成对。如(12)
3.实现整型数组的排序和反转

package com.bmwm5gtr.test;

public class ArrayClass{
	
	/**
	 * 此方法将数组进行反转
	 * @param number
	 * @return
	 */
	public static String inverse(int[] number){
		int temp=0;
		int count=0;
		for(int i=0;i<number.length;i++){							
			count=number.length-i-1;
			if(i>=count)
				break;
			else{
				temp=number[count];
				number[count]=number[i];
				number[i]=temp;
			}
		}
		return printF(number,"inverse");
	}
	
	/**
	 * 对数组进行排序，从小到大和从大到小
	 * @param number
	 * @param operType
	 */
	public static String sort(int[] number,String operType){
		int tem=0;
		for(int i=0;i<number.length;i++){
			for(int j=number.length-1;j>i;j--){
				if("minToMax".equalsIgnoreCase(operType)){
					if(number[i]>number[j]){
						tem=number[i];
						number[i]=number[j];
						number[j]=tem;
					}			
				}else{
					if(number[i]<number[j]){
						tem=number[i];
						number[i]=number[j];
						number[j]=tem;
					}
				}				
			}			
		}
		return printF(number,operType);
	}
	
	/**
	 * 改方法负责打印数组
	 * @param number
	 * @return
	 */
	public static String printF(int[] number,String operType){
		String cnName=("inverse".equalsIgnoreCase(operType))?"反转":("minToMax".equalsIgnoreCase(operType)?"从小到大排序":("maxToMin".equalsIgnoreCase(operType)?"从大到小排序":"初始化"));
		cnName+="后：";
		for(int x:number){
			cnName+=x+"-->";
		}
		
		return cnName.substring(0, cnName.length()-3);
	}
}

package com.bmwm5gtr.test;


public class ArrayDemo{
	public static void main(String args[]){
		int[] number={47,10,12,89,1,87,15,43,22};
		System.out.println(ArrayClass.printF(number,"normal"));
		System.out.println(ArrayClass.inverse(number));
		System.out.println(ArrayClass.sort(number,"minToMax"));
		System.out.println(ArrayClass.sort(number,"maxToMin"));
	}
};