- 浏览: 784474 次
- 性别:
- 来自: 西安
-
文章分类
最新评论
-
wangyudong:
新版本 Wisdom RESTClienthttps://gi ...
jersery client调用REST框架web services服务的一个示例 -
wangyudong:
很多REST Client是不支持自动化测试RESTful A ...
jersery client调用REST框架web services服务的一个示例 -
doubledumbao:
感谢你的代码,在使用中发现两处小问题,已经做了修改,再次感谢。 ...
Java Zip Utils 压缩/解压缩工具包 -
doubledumbao:
package com.ry.messagedigest;
...
Java Zip Utils 压缩/解压缩工具包 -
phrmgb:
对wsdl讲解的很细致,收藏
Web Service (二) WSDL详解
因为gson网上的帮助文档打开时比较慢,所以把帮助文档摘录如此,方便查看:
1. 基本类型转化
public static void main(String[] args) { Gson gson = new Gson(); System.out.println(gson.toJson(1)); // ==> prints 1 System.out.println(gson.toJson("abcd"));// ==> prints "abcd" System.out.println(gson.toJson(new Long(10)));// ==> prints 10 int[] values = { 1 }; System.out.println(gson.toJson(values));// ==> prints [1] System.out.println("============"); int one = gson.fromJson("1", int.class); Integer one1 = gson.fromJson("1", Integer.class); Long one2 = gson.fromJson("1", Long.class); String str = gson.fromJson("\"abc\"", String.class); String anotherStr = gson.fromJson("[\"abc\"]", String.class); int[] ints = gson.fromJson("[1,2,3,4,5]", int[].class); Boolean b = gson.fromJson("false", Boolean.class); System.out.println(b == false); //==> prints true }
2.对象转化
public class BagOfPrimitives { private int value1 = 1; private String value2 = "abc"; //是用于声明变量在序列化的时候不被存储 private transient int value3 = 3; BagOfPrimitives() { // no-args constructor } public static void main(String[] args) { BagOfPrimitives obj = new BagOfPrimitives(); Gson gson = new Gson(); String json = gson.toJson(obj); System.out.println(json); //==> json is {"value1":1,"value2":"abc"} BagOfPrimitives obj2 = gson.fromJson(json, BagOfPrimitives.class); System.out.println(obj2.value1); System.out.println(obj2.value2); System.out.println(obj2.value3);//==>3 String json1 = "{'value1':1,'value2':'abc','value3':4}"; BagOfPrimitives obj3 = gson.fromJson(json1, BagOfPrimitives.class); System.out.println(obj3.value1); System.out.println(obj3.value2); System.out.println(obj3.value3); //==>3 } }
Note that you can not serialize objects with circular references since that will result in infinite recursion.
如果要是用json lib的话,上面的代码可以写成如下所示:
String json1 = "{'value1':1,'value2':'abc','value3':4}"; JSONObject jsonObj = JSONObject.fromObject( json1 ); BagOfPrimitives obj3 = (BagOfPrimitives) JSONObject.toBean( jsonObj, BagOfPrimitives.class );
Finer Points with Objects
- It is perfectly fine (and recommended) to use private fields
- There
is no need to use any annotations to indicate a field is to be included
for serialization and deserialization. All fields in the current class
(and from all super classes) are included by default.
- If a field is marked transient, (by default) it is ignored and not included in the JSON serialization or deserialization.
- This implementation handles nulls correctly
- While serialization, a null field is skipped from the output
- While deserialization, a missing entry in JSON results in setting the corresponding field in the object to null
- If a field is synthetic
, it is ignored and not included in JSON serialization or deserialization
- Fields corresponding to the outer classes in inner classes, anonymous classes, and local classes are ignored and not included in serialization or deserialization
Nested Classes (including Inner Classes)
public class A { public String a; class B { public String b; public B() { // No args constructor for B } } }
NOTE : The above class B can not (by default) be serialized with Gson.
G s o n c a n n o t d e serialize {"b":"abc"} into an instance of B since the class B is an inner class. if it was defined as static class B then Gson would have been able to deserialize the string. Another solution is to write a custom instance creator for B.
public class InstanceCreatorForB implements InstanceCreator<A.B> { private final A a; public InstanceCreatorForB(A a) { this.a = a; } public A.B createInstance(Type type) { return a.new B(); } }
The above is possible, but not recommended.
数组例子:
Gson gson = new Gson(); int[] ints = {1, 2, 3, 4, 5}; String[] strings = {"abc", "def", "ghi"}; (Serialization) gson.toJson(ints); ==> prints [1,2,3,4,5] gson.toJson(strings); ==> prints ["abc", "def", "ghi"] (Deserialization) int[] ints2 = gson.fromJson("[1,2,3,4,5]", int[].class); ==> ints2 will be same as ints
We also support multi-dimensional arrays, with arbitrarily complex element types
综合实例1:
public class ExampleBean { private String name; private String id; private int age; private boolean isOk; public ExampleBean(String name, String id, int age, boolean isOk) { super(); this.name = name; this.id = id; this.age = age; this.isOk = isOk; } public ExampleBean() { } //setter和getter方法 }
测试:
public static void main(String[] args) { Gson gson = new Gson(); List<ExampleBean> list = new ArrayList<ExampleBean>(); for (int i = 0; i < 5; i++) { String name = "xxlong" + i; int age = 20 + i; ExampleBean bean = new ExampleBean(name, i + "", age); list.add(bean); } Type listType = new TypeToken<List<ExampleBean>>() { }.getType(); //将list转化成json字符串 String json = gson.toJson(list); System.out.println(json); //将json字符串还原成list List<ExampleBean> list2 = gson.fromJson(json, listType); }
输出如下:[{"name":"xxlong0","id":"0","age":20,"isOk":false},{"name":"xxlong1","id":"1","age":21,"isOk":false},{"name":"xxlong2","id":"2","age":22,"isOk":false},{"name":"xxlong3","id":"3","age":23,"isOk":false},{"name":"xxlong4","id":"4","age":24,"isOk":false}]
综合实例2:
需求:想将字符串{'tableName' :'ys_index_y','year': '2008','params':'[z_expense,z_expense_profit,z_main_margin]','isOperAll':'false','copyToYear':''}还原成对象OpeerConditions,OpeerConditions对象代码如下所示:
public class OperConditions { private String tableName; private String year; private String[] params; private boolean isOperALl; private String copyToYear; public OperConditions() { } public OperConditions(String tableName, String year, String[] params, boolean isOperALl, String copyToYear) { super(); this.tableName = tableName; this.year = year; this.params = params; this.setOperALl(isOperALl); this.copyToYear = copyToYear; } //getter和setter方法 }
因为OperConditions中有属性params,它是一个数组,所以无论是用json lib还是gson都不能直接将上面的字符串还原成OperCondtions对象,可以直接将params分离出来,单独处理,我这里选用此种方法来处理:
json-lib代码如下:
public static void main(String[] args) { String json = "{'tableName' :'ys_index_y','year': '2008','isOperAll':'false','copyToYear':''}"; JSONObject jsonObj = JSONObject.fromObject( json ); OperConditions conditions = (OperConditions) JSONObject.toBean( jsonObj, OperConditions.class ); System.out.println(conditions.isOperALl() == false); //==>输出为true String json1 = "['z_expense','z_expense_profit','z_main_margin']"; JSONArray jsonArray = JSONArray.fromObject(json1); //List<String> list = jsonArray.toList(jsonArray); //这个方法也可以 List<String> list = jsonArray.toList(jsonArray,String.class); conditions.setParams(list.toArray(new String[0])); System.out.println(conditions.getParams()[0]); //==>输出为z_expense }
因为JSONArray的toArray()方法返回的是一个Object[]数组,所以先将它转化成list,再转化到String数组。
当然由JSONArray转化成list时也可以使用subList方法,如下所示:
List<String> list = jsonArray.subList(0, jsonArray.size());
或者可以直接使用JSONArray的iterator()
方法迭代它本身直接得到需要的String数组。
如果使用Gson来完成这一需求,个人感觉更简单,代码如下所示:
public static void main(String[] args) { String json = "{'tableName' :'ys_index_y','year': '2008','isOperAll':'false','copyToYear':''}"; Gson gson = new Gson(); OperConditions conditions = gson.fromJson(json, OperConditions.class); System.out.println(conditions.isOperALl() == false); // ==>输出为true String json1 = "['z_expense','z_expense_profit','z_main_margin']"; String[] params = gson.fromJson(json1,String[].class); conditions.setParams(params); System.out.println(conditions.getParams()[0]); // ==>输出为z_expense }
Gson可以直接转化成String[]数组,同时转化OperConditions时也比json-lib简单。
还有一点是非常值得注意的,就是你的bean中有boolean属性值时,强烈建议你别像我这个例子中一样命名为以is开头的属性名,这可能给你带来意想不到的错误,关于这一点的详细解说请参看我的文章json lib 学习笔记
发表评论
-
JS回到顶部效果
2013-05-22 23:01 1270<%@ page contentType=" ... -
JS将网站添加到收藏夹
2013-05-22 21:23 3845function addToFavorite(){ ... -
企信通项目前端开发笔记
2012-10-09 15:38 0/* * 根据元素标签名及类名查找符合要求的 ... -
选择框(select)添加或者减少选项(option)操作的js代码
2012-10-09 15:40 2078选择框(select)添加或者减少选项(option)操作的j ... -
常用的js较验集锦
2011-12-12 10:08 10541.去空格 第一种方法 function ltrim ... -
最近做项目遇到的有关jqGrid和jstree的问题
2010-05-24 17:44 4208一、query.jqGrid-3.6.4 css: 首 ... -
JavaScript concat方法和join方法及性能测试
2010-03-24 14:07 2747一. concat方法 1. String中的conca ... -
jquery性能优化技巧(二)
2010-03-23 18:02 1895本文转载自: http://www.b ... -
jquery性能优化技巧(一)
2010-03-23 17:37 2516本文参考自: http://www.b ... -
强烈推荐:240多个jQuery插件
2010-03-23 13:32 1043本文转载自:http://www.cnblogs.com/te ... -
json lib 学习笔记
2010-01-30 12:01 8472json-lib demo JSON-lib这个Ja ... -
JQuery UI accordion学习笔记
2010-01-09 15:44 9349JQuery UI accordion学习笔记 ...
相关推荐
这个学习笔记主要围绕`json-lib`的使用方法和关键特性进行阐述。 首先,`json-lib`支持多种Java对象到JSON的转换,包括基本类型、数组、集合、Map以及自定义的Java类。例如,你可以通过以下方式将一个HashMap转换为...
3. JSON对象与JSON数组的创建:学习笔记可能介绍如何使用JSON-lib创建JSON对象和数组。例如,你可以通过`net.sf.json.JSONObject`和`net.sf.json.JSONArray`类来实现。 4. Java对象转换为JSON:JSON-lib提供了`...
在Android客户端,解析JSON数据通常使用`org.json`库(已包含在Android SDK中)或者第三方库如Gson、Jackson、FastJson等。以下是一个使用`org.json`库解析JSON对象的例子: ```java import org.json.JSONArray; ...
例如,Apache Tomcat服务器需要的Servlet和JSP API,Spring框架的库,Hibernate的ORM库,或者JSON解析库(如Jackson或Gson)。开发者在构建项目时,会将这些库添加到类路径(classpath)中,使得项目在编译和运行时...
服务器返回的数据通常以JSON格式呈现,客户端需要解析JSON数据,可以使用Gson、Jackson或org.json等库进行解析。 14. 处理servlet中乱码 在Servlet中处理乱码问题,需要确保请求参数的编码与服务器接收的编码一致,...