Snooker
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3298 Accepted Submission(s): 1383
Problem Description
background:
Philip likes to play the QQ game of Snooker when he wants a relax, though he was just a little vegetable-bird. Maybe you hadn't played that game yet, no matter, I'll introduce the rule for you first.
There are 21 object balls on board, including 15 red balls and 6 color balls: yellow, green, brown, blue, pink, black.
The player should use a white main ball to make the object balls roll into the hole, the sum of the ball's fixed value he made in the hole is the player's score. The player should firstly made a red ball into the hole, after that he gains red-ball's value(1 points), then he gets the chance to make a color ball, then alternately. The color ball should be took out until all the red-ball are in the hole. In other word, if there are only color balls left on board, the player should hit the object balls in this order: yellow(2 point), green(3 point), brown(4 point), blue(5 point), pink(6 point), black(7 point), after the ball being hit into the hole, they are not get out of the hole, after no ball left on board, the game ends, the player who has
the higher score wins the game. PS: red object balls never get out of the hole.
I just illustrate the rules that maybe used, if you want to contact more details, visit http://sports.tom.com/snooker/ after
the contest.
for example, if there are 12 red balls on board(if there are still red ball left on board, it can be sure that all the color
balls must be on board either). So suppose Philp can continuesly hit the ball into the hole, he can get the maximun score is
12 * 1 (12 red-ball in one shoot) + 7 * 12(after hit a red ball, a black ball which was the most valuable ball should be the target) + 2 + 3 + 4 + 5 + 6 + 7(when no red ball left, make all the color ball in hole).
Now, your task is to judge whether Philip should make the decision to give up when telling you the condition on board(How many object balls still left not in the hole and the other player's score). If Philp still gets the chance to win, just print "Yes", otherwise print "No". (PS: if the max score he could get on board add his current score is equal to the opponent's current score, still output "Yes")
Input
The first line contains a numble N indicating the total conditions. Then followed by N lines, each line is made of three integers:
Ball_Left P_Score O_Score represeting the ball number left on board, Philp's current score, and the opponent's current score.
All the input value are in 32 bit integer value range.
Output
You should caculate the max score left Philp can gain, and judge whether he has the possiblity to win.
Sample Input
2
12 1 1
1 30 39
Sample Output
Yes
No
题意:斯诺克,给三个数,第一个数代表还剩的球数,第二个代表Philp当前的分数,第三个代表opponent当前的分数,求Philp是否还有赢的可能,如果可能输出yes,否则输出no
#include <iostream>
using namespace std;
int main()
{
int a, b, c, i;
int t;
cin>>t;
while(t--)
{
cin>>a>>b>>c;
for(i = 1; i <= a; i++)
{
if(a - i >= 6)
b += 8;
else
b += 7 - (a - i);
}
if(b >= c)
cout<<"Yes"<<endl;
else
cout<<"No"<<endl;
}
return 0;
}
分享到:
相关推荐
HDU(杭州电子科技大学在线评测系统)是一个深受程序员喜爱的在线编程练习平台,它提供了丰富的算法题目供用户挑战,帮助他们提升编程技能和算法理解能力。"hdu.rar_hdu"这个压缩包文件很可能是某位程序员整理的他在...
【标题】"HDU_2010.rar"是一个压缩包文件,其中包含了与"HDU 2010"相关的资源,特别是针对"HDU ACM20"比赛的编程题目。"hdu 2010"和"hdu 20"可能是该比赛的不同简称或分类,而"hdu acm20"可能指的是该赛事的第20届...
【标题】"HDU题目java实现"所涉及的知识点主要集中在使用Java编程语言解决杭州电子科技大学(HDU)在线评测系统中的算法问题。HDU是一个知名的在线编程竞赛平台,它提供了大量的算法题目供参赛者练习和提交解决方案...
ACM HDU 题目分类 ACM HDU 题目分类是指对 HDU 在线判题系统中题目的分类,总结了大约十来个分类。这些分类将有助于编程选手更好地理解和解决问题。 DP 问题 DP(Dynamic Programming,动态规划)是一种非常重要...
### hdu1250高精度加法 #### 背景介绍 在计算机科学与编程竞赛中,处理大整数运算(特别是加法、减法、乘法等)是常见的需求之一。当数字的位数超过了标准数据类型(如`int`、`long`等)所能表示的最大值时,就需要...
【标题】"hdu.rar_HDU 1089.cpp_OJ题求和_hdu_horsekw5_杭电obj" 提供的信息是关于一个压缩文件,其中包含了一个名为 "HDU 1089.cpp" 的源代码文件,这个文件是为了解决杭州电子科技大学(Hangzhou Dianzi ...
【标题】"HDU DP动态规划"涉及到的是在算法领域中的动态规划(Dynamic Programming,简称DP)技术,这是解决复杂问题的一种高效方法,尤其适用于有重叠子问题和最优子结构的问题。动态规划通常用于优化多阶段决策...
HDU1059的代码
hdu1001解题报告
hdu 1574 passed sorce
【ACM HDU】指的是在ACM(国际大学生程序设计竞赛,International Collegiate Programming Contest)中,参赛者在杭州电子科技大学(Hangzhou Dianzi University,简称HDU)的在线评测系统上完成并已解决的题目集合...
hdu2101AC代码
【标题】:杭电ACMhdu1163 【描述】:这是一道源自杭州电子科技大学(Hangzhou Dianzi University,简称HDU)的ACM编程竞赛题目,编号为1163。这类问题通常需要参赛者利用计算机编程解决数学、逻辑或算法上的挑战,...
HDU是杭州电子科技大学(Hangzhou Dianzi University)举办的一个在线编程竞赛平台,全称为HDU Online Judge。ACM是国际大学生程序设计竞赛(International Collegiate Programming Contest)的缩写,是一个全球性的...
【标题】"HDU.rar_hdu_hdu07_com_shownv9b_www.563hdu." 暗示这是一个与HDU(杭州电子科技大学在线编程平台)相关的压缩包,其中可能包含了该平台上的编程竞赛题目或练习题目的源代码。"hdu07"可能是某个特定题目的...
hdu 5007 Post Robot 字符串枚举。 暴力一下就可以了。
【ACM入门与提高:HDU ACM竞赛课程详解】 ACM(国际大学生程序设计竞赛,International Collegiate Programming Contest,简称ICPC或ACM/ICPC)是一项全球性的竞赛,旨在激发大学生对计算机科学的兴趣,提升他们的...
【标题】"hdu_acm_1084.rar_ACM_HDU10_acm10_hdu_hdu 1084" 提供的是一个关于杭电(HDU)ACM竞赛第1084题的解决方案。该题目可能是在编程竞赛中常见的算法问题,而ACM(国际大学生程序设计竞赛)是全球知名的编程...
hdu 1166线段树代码
HDU(Hangzhou Dianzi University)是国内外知名的在线编程竞赛平台,主要服务于ACM/ICPC(国际大学生程序设计竞赛)以及相关的算法训练。"HDU最全ac代码"这个压缩包很可能是包含了在HDU平台上解题通过的完整源代码...