Problem Statement
A sentence is composed of words, spaces and punctuation. For this problem, words are maximal contiguous strings of letters. Given a sentence, sort the words in the sentence while preserving the spaces and punctuation. Sorting is case sensitive, so uppercase letters precede lowercase letters. Return the newly constructed sentence.
Example: "The big, brown dog ran down the street!"
Returns: "The big, brown dog down ran street the!"
Observe the space and punctuation preservation between the original sentence and the resulting sentence.
Definition
Class:
SuperSort
Method:
wordSort
Parameters:
String
Returns:
String
Method signature:
String wordSort(String sentence)
(be sure your method is public)
Notes
-
Watch out for multiple consecutive spaces (they should be preserved).
Constraints
-
sentence will contain between 1 and 50 characters, inclusive.
-
Each character in sentence will be either a letter ('a'-'z', 'A'-'Z'), ' ', '.', ',', '!' or '?'.
Examples
0)
"The big, brown dog ran down the street!"
Returns: "The big, brown dog down ran street the!"
1)
"This is the first sentence of the paragraph."
Returns: "This first is of paragraph sentence the the."
2)
"t.d,a!f?g.b,q!i?p.h,s!u?m.l,e!v?y.c,j!w?k.n,x!o?r."
Returns: "a.b,c!d?e.f,g!h?i.j,k!l?m.n,o!p?q.r,s!t?u.v,w!x?y."
3)
"What is this?"
Returns: "What is this?"
4)
"? . , ! "
Returns: "? . , ! "
5)
" "
Returns: " "
6)
"faecdb"
Returns: "faecdb"
7)
"a A b B c C d D e E"
Returns: "A B C D E a b c d e"
import java.util.*;
public class SuperSort {
public static String wordSort(String sent) {
LinkedList<String> words = new LinkedList<String>();
Map<Integer, String> tokens = new HashMap<Integer, String>();
int n = sent.length(), count = 0;
for (int s = 0, t = 0; s < n;) {
for (s = t; t < n && Character.isLetter(sent.charAt(t)); t++) ;
if (t > s) {
words.add(sent.substring(s, t));
count++;
}
for (s = t; t < n && !Character.isLetter(sent.charAt(t)); t++) ;
if (t > s)
tokens.put(count++, sent.substring(s, t));
}
Collections.sort(words);
StringBuilder sb = new StringBuilder();
for (int i = 0; i < count; i++)
sb.append(tokens.containsKey(i) ? tokens.get(i) : words.poll());
return sb.toString();
}
}
发表评论
-
TCHS-12-950
2010-03-01 12:58 784Problem Statement ... -
TCHS-12-550
2010-03-01 10:04 707Problem Statement ... -
TCHS-12-250
2010-02-28 09:53 721Problem Statement ... -
TCHS-11-1000
2010-02-22 15:22 671Problem Statement ... -
TCHS-11-500
2010-02-22 13:11 799Problem Statement ... -
TCHS-11-250
2010-02-22 11:38 721Problem Statement ... -
TCHS-10-1000
2010-02-21 16:35 690Problem Statement ... -
TCHS-10-500
2010-02-21 15:16 765Problem Statement ... -
TCHS-10-250
2010-02-21 14:26 768Problem Statement ... -
TCHS-9-1000
2010-02-20 18:45 704Problem Statement ... -
TCHS-9-500
2010-02-20 16:26 1328Problem Statement ... -
TCHS-9-250
2010-02-20 15:24 690Problem Statement ... -
TCHS-8-1000
2010-02-19 11:57 687Problem Statement ... -
TCHS-8-500
2010-02-19 10:56 760Problem Statement ... -
TCHS-8-250
2010-02-19 10:18 615Problem Statement ... -
TCHS-7-1000
2010-02-05 15:21 692Problem Statement ... -
TCHS-7-500
2010-02-05 13:45 693Problem Statement ... -
TCHS-7-250
2010-02-05 13:32 781Problem Statement ... -
TCHS-6-900
2010-02-04 12:06 676Problem Statement ... -
TCHS-6-600
2010-02-04 11:33 709Problem Statement ...
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