hibernate Restrictions用法

方法说明

Restrictions.eq      ＝

Restrictions.allEq    利用Map来进行多个等于的限制

Restrictions.gt      ＞

Restrictions.ge      ＞＝

Restrictions.lt        ＜

Restrictions.le       ＜＝

Restrictions.between      BETWEEN

Restrictions.like       LIKE

Restrictions.in         in

Restrictions.and       and

Restrictions.or          or

Restrictions.sqlRestriction          用SQL限定查询


QBC常用限定方法

Restrictions.eq --> equal,等于.

Restrictions.allEq --> 参数为Map对象,使用key/value进行多个等于的比对,相当于多个Restrictions.eq的效果

Restrictions.gt --> great-than > 大于

Restrictions.ge --> great-equal >= 大于等于

Restrictions.lt --> less-than, < 小于

Restrictions.le --> less-equal <= 小于等于

Restrictions.between --> 对应SQL的between子句

Restrictions.like --> 对应SQL的LIKE子句

Restrictions.in --> 对应SQL的in子句

Restrictions.and --> and 关系

Restrictions.or --> or 关系

Restrictions.isNull --> 判断属性是否为空,为空则返回true

Restrictions.isNotNull --> 与isNull相反

Restrictions.sqlRestriction --> SQL限定的查询

Order.asc --> 根据传入的字段进行升序排序

Order.desc --> 根据传入的字段进行降序排序

MatchMode.EXACT --> 字符串精确匹配.相当于"like 'value'"

MatchMode.ANYWHERE --> 字符串在中间匹配.相当于"like '%value%'"

MatchMode.START --> 字符串在最前面的位置.相当于"like 'value%'"

MatchMode.END --> 字符串在最后面的位置.相当于"like '%value'"

例子
查询年龄在20-30岁之间的所有学生对象
List list = session.createCriteria(Student.class)
      .add(Restrictions.between("age",new Integer(20),new Integer(30)).list();
查询学生姓名在AAA,BBB,CCC之间的学生对象
String[] names = {"AAA","BBB","CCC"};
List list = session.createCriteria(Student.class)
      .add(Restrictions.in("name",names)).list();
查询年龄为空的学生对象
List list = session.createCriteria(Student.class)
      .add(Restrictions.isNull("age")).list();
查询年龄等于20或者年龄为空的学生对象
List list = session.createCriteria(Student.class)
      .add(Restrictions.or(Restrictions.eq("age",new Integer(20)),
                 Restrictions.isNull("age")).list();

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使用QBC实现动态查询
public List findStudents(String name,int age){

Criteria criteria = session.createCriteria(Student.class);
if(name != null){
  criteria.add(Restrictions.liek("name",name,MatchMode.ANYWHERE));
}
if(age != 0){
  criteria.add(Restrictions.eq("age",new Integer(age)));
}
criteria.addOrder(Order.asc("name"));//根据名字升序排列
return criteria.list();
}



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下面的代码写的不易读.其实核心就是一句
Restrictions.or(Restrictions.like(),Restrictions.or(Restrictions.like,........))
里面的or可以无限加的.还是比较好用

Session session = getHibernateTemplate().getSessionFactory()
                .openSession();
        Criteria criteria = session.createCriteria(Film.class);
        List<Film> list = criteria.add(
            Restrictions.or(Restrictions.like("description", key,MatchMode.ANYWHERE),
            Restrictions.or(Restrictions.like("name", key,MatchMode.ANYWHERE),
                Restrictions.or(    Restrictions.like("direct", key,MatchMode.ANYWHERE),
                Restrictions.or(Restrictions.like("mainplay",key,MatchMode.ANYWHERE),
                        Restrictions.like("filearea", key,MatchMode.ANYWHERE)))))).list();

        session.close();
        return list;