时间校验

import java.util.regex.Pattern;


/**
* 检日期
* @param value
* @param datePattern
* @return
*/
public static boolean validateDate(String value) {
Pattern p = Pattern.compile("^((\\d{2}(([02468][048])|([13579][26]))[\\/\\/\\s]?((((0?" +
  "[13578])|(1[02]))[\\/\\/\\s]?((0?[1-9])|([1-2][0-9])|(3[01])))" +
  "|(((0?[469])|(11))[\\/\\/\\s]?((0?[1-9])|([1-2][0-9])|(30)))|" +
  "(0?2[\\/\\/\\s]?((0?[1-9])|([1-2][0-9])))))|(\\d{2}(([02468][12" +
  "35679])|([13579][01345789]))[\\/\\/\\s]?((((0?[13578])|(1[02]))" +
  "[\\/\\/\\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))" +
  "[\\/\\/\\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\\/\\/\\s]?((0?[" +
  "1-9])|(1[0-9])|(2[0-8]))))))");
  //(\\s(((0?[0-9])|([1-2][0-3]))\\:([0-5]?[0-9])((\\s)|(\\:([0-5]?[0-9])))))?$ 时分000000
  String s = value.replaceAll("-", "/");
  return p.matcher(s).matches();

}


/**
* 判断是否为有效数字
* @author gGW11348
* @param value
* @return
*/
public static boolean validateNumber(String value){
Pattern p = Pattern.compile("\\d*\\.?\\d*");
return p.matcher(value).matches();
}