登录/注册后跳回登录/注册前的页面实现方法

 

网站开发中经常会遇到这样的问题，登录后自动转到了首页或者用户管理首页，这样有时候会让用户觉得很不方便，特别是电子商务类的网站，当用于在浏览产品页面时，需要购买，但是只有登录后的用户才能进入购买页面，所以如果当用户登录后进入的不是他登录前的产品浏览页面，他得去重新找，这是非常不友好的。

可以通过request.getHeader("referer");方式来实现登录/注册后返回进入登录或注册页面前的页面

举例:

java 代码

/**
 * 进入到登录页面
 * @param mapping
 * @param form
 * @param request
 * @param response
 * @return
 */
public
 ActionForward loginview(ActionMapping mapping, ActionForm form,
        HttpServletRequest request, HttpServletResponse response) {

    
//登录后跳转回进来的页面，如果进来之前的页面是登录和退出，则登录后跳转到首页
    String pagefrom = request.getHeader(
"referer"
);
    
if
(pagefrom.indexOf(
"method=login"
)>
0
 || pagefrom.indexOf(
"method=logout"
)>
0
)
    {
        pagefrom = pagefrom.substring(
0
,pagefrom.lastIndexOf(
"/"
)+
1
);
    }
    request.setAttribute(
"pagefrom"
, pagefrom);

    saveToken(request);

    User object = 
null
;
    
try
 {
        object = entityClass.newInstance();
    } 
catch
 (InstantiationException e) {
        log.error(e);
    } 
catch
 (IllegalAccessException e) {
        log.error(e);
    }
    initForm(form, request, object);
    
return
 mapping.findForward(LOGINVIEW);
}

 

在登录页面中设置hidden元素：

登录页面部分代码

<
html:form
 
action
=
"/userm.do"
 
focus
=
"loginname"
 
styleClass
=
"u_login_form"
 
onsubmit
=
"return validateUserForm(this)"
>
                
<
input
 
type
=
"hidden"
 
name
=
"method"
 
value
=
"login"
/>
                
<
input
 
type
=
"hidden"
 
name
=
"pagefrom"
 
value
=
"${ pagefrom }"
/>
                
<
input
 
type
=
"hidden"
 
name
=
"name"
 
value
=
"name"
/>
                
<
input
 
type
=
"hidden"
 
name
=
"mail"
 
value
=
"[e-mail]"
/>
                
<
div
 
class
=
"l"
>
<
img
 
src
=
"${css}/images/login_icon_01.gif"
 
/>
div
>
                
<
div
 
class
=
"l"
>
                    
<
html:text
 
property
=
"loginname"
 
styleClass
=
"text"
/>
<
br
 
/>
                    
<
html:password
 
property
=
"password"
 
styleClass
=
"text"
/>
<
br
 
/>
                    
<
%@ include 
file
=
"/commons/messages.jsp"
 %
>
                
div
>
                
<
div
 
class
=
"l"
>
<
html:img
 
src
=
"${css}/images/login_icon_02.gif"
 
onclick
=
"if(validateUserForm(document.userForm)) document.userForm.submit();"
/>
div
>
                
<
div
 
class
=
"c"
>
div
>
            
html:form
>
            
<
html:javascript
 
formName
=
"userForm"
 
staticJavascript
=
"false"
 
dynamicJavascript
=
"true"
 
cdata
=
"false"
/>
            
<
script
 
type
=
"text/javascript"
 
src
=
"${ctx}/scripts/validator.jsp"
>
script
>

 

根据登录页面中的pagefrom元素的值，在登录成功后跳转到该值对应的页面

登录代码：

java 代码

    
/**
     * 登录
     * @param mapping
     * @param form
     * @param request
     * @param response
     * @return
     */
    
public
 ActionForward login(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response) {
        String pagefrom = request.getParameter(
"pagefrom"
);
        request.setAttribute(
"pagefrom"
, pagefrom);

        
if
 (isCancelled(request))
            
return
 list(mapping, form, request, response);
        
if
 (!isTokenValid(request)){
            saveDirectlyError(request, 
"重复提交"
);
            
return
 mapping.findForward(LOGINVIEW);
        }
//      resetToken(request);

        
// run validation rules on this form
        ActionMessages errors = form.validate(mapping, request);
        
if
 (!errors.isEmpty()) {
            saveErrors(request, errors);
            refrenceData(request);
            
return
 mapping.findForward(LOGINVIEW);
        }



        User object = doNewEntity(form, request);
        initEntity(form, request, object);

        User user = userManagerCommon.checkPassword(object.getLoginname(), object.getPassword());
        
if
(
null
==user)
        {
            errors.add(
"password"
,
new
 ActionMessage(
"user.missing"
,object.getPassword()));
            saveErrors(request, errors);
            
return
 mapping.findForward(LOGINVIEW);
        }

        SessionUser.saveSession(request,user);


        
try
 {
            response.sendRedirect(pagefrom);
            
return
 
null
;
        } 
catch
 (IOException e) {
            e.printStackTrace();
        }

        
return
 mapping.findForward(INDEX);
    }

 

第48行的代码就实现了跳转。