Java每日一题14

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程序经过一系列处理，得到两个string类型的时间值，一个值的形式为：“2008-05-09”，一个形式为“2008-5-13”，如何比较他们之间相差的天数？

package test61;
//package com.color.program; 

import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;

public class CompareTime {

	public static void main(String[] args) {
		String t1 = "2009-02-03";
		String t2 = "2009-04-28";

		try {
			System.out.println(CompareTime.getBetweenDays(t1, t2));
		} catch (ParseException e) {
			e.printStackTrace();
		}
	}

	/**
	 * 取得两个时间段的时间间隔
	 * 
	 * @author color
	 * @param t1
	 *            时间1
	 * @param t2
	 *            时间2
	 * @return t2 与t1的间隔天数
	 * @throws ParseException
	 *             如果输入的日期格式不是0000-00-00 格式抛出异常
	 */
	public static int getBetweenDays(String t1, String t2)
			throws ParseException {
		DateFormat format = new SimpleDateFormat("yyyy-MM-dd");
		int betweenDays = 0;
		Date d1 = format.parse(t1);
		Date d2 = format.parse(t2);
		Calendar c1 = Calendar.getInstance();
		Calendar c2 = Calendar.getInstance();
		c1.setTime(d1);
		c2.setTime(d2);
		// 保证第二个时间一定大于第一个时间
		if (c1.after(c2)) {
			c1 = c2;
			c2.setTime(d1);
		}
		int betweenYears = c2.get(Calendar.YEAR) - c1.get(Calendar.YEAR);
		betweenDays = c2.get(Calendar.DAY_OF_YEAR)
				- c1.get(Calendar.DAY_OF_YEAR);
		for (int i = 0; i < betweenYears; i++) {
			c1.set(Calendar.YEAR, (c1.get(Calendar.YEAR) + 1));
			betweenDays += c1.getMaximum(Calendar.DAY_OF_YEAR);
		}
		return betweenDays;
	}

}

我觉得应该有其他的方法，大家群策群力，欢迎回帖：）

评论

7 楼 ydsakyclguozi 2009-02-24  

aben6448 写道

Java代码

public long getBetweenDays(String begindate,String enddate) throws ParseException{   
        SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd");   
        Date begin=sdf.parse(begindate);   
        Date end=sdf.parse(enddate);   
        long betweenDays=(end.getTime()-begin.getTime())/(24*60*60*1000);   
        return betweenDays;   
    }  public long getBetweenDays(String begindate,String enddate) throws ParseException{
SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd");
Date begin=sdf.parse(begindate);
Date end=sdf.parse(enddate);
long betweenDays=(end.getTime()-begin.getTime())/(24*60*60*1000);
return betweenDays;
}

认为这个才是经典

6 楼 shanke-2004 2009-02-24  

很不错！。。

5 楼 ccxw1983 2009-02-23  

楼主的办法太笨拙了，慢慢来吧

4 楼 kakaluyi 2009-02-21  

aben6448经常提出好方法啊呵呵

3 楼 dandy 2009-02-20  

public long getBetweenDays(String begindate,String enddate) throws ParseException{   
        SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd");   
        Date begin=sdf.parse(begindate);   
        Date end=sdf.parse(enddate);   
        long betweenDays=(end.getTime()-begin.getTime())/(24*60*60*1000);   
        return betweenDays;   
    } 

这个挺好的！

2 楼 jythoner 2009-02-20  

aben6448 写道

Java代码 public long getBetweenDays(String begindate,String enddate) throws ParseException{          SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd");          Date begin=sdf.parse(begindate);          Date end=sdf.parse(enddate);          long betweenDays=(end.getTime()-begin.getTime())/(24*60*60*1000);          return betweenDays;      }  public long getBetweenDays(String begindate,String enddate) throws ParseException{
SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd");
Date begin=sdf.parse(begindate);
Date end=sdf.parse(enddate);
long betweenDays=(end.getTime()-begin.getTime())/(24*60*60*1000);
return betweenDays;
}

这个也不错

1 楼 aben6448 2009-02-20  

public long getBetweenDays(String begindate,String enddate) throws ParseException{
		SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd");
		Date begin=sdf.parse(begindate);
		Date end=sdf.parse(enddate);
		long betweenDays=(end.getTime()-begin.getTime())/(24*60*60*1000);
		return betweenDays;
	}