通过url地址解析xml

public static String getXmlUrl(String arg,String encoding){
                String result= "";
                try{
                        URL url=new URL(arg);
                        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
                        conn.setDoOutput(true);
                        conn.connect();

                        InputStream is = conn.getInputStream();
                        BufferedReader br = new BufferedReader(new InputStreamReader(is,encoding));
                       
                        StringBuffer sp=new StringBuffer();
                        String str=null;
                        while((str=br.readLine())!=null){
                                sp.append(str+"\r\n");
                        }
                        result = sp.toString();
                       
                        br.close();
                        conn.disconnect();
                }catch(Exception e){
                        System.err.println("[公文归档同步]转换XML异常!");
                        System.err.println(e);
                        e.printStackTrace();
                }
                return result;
}