go语言结构体对象按照时间对象排序

获取用户列表，按照申请时间倒序排序，注：调用标准库的sort.Sort必须要先实现Len(),Less(),Swap() 三个方法.



......
import (
"fmt"
"io/ioutil"
"sort"
"time"
)

type User struct {
ApplicantGuid string `json:"applicant_guid"`
ApplyTime string `json:"apply_time"`
UsedLicense int `json:"used_license"`
Applicant string `json:"applicant"`
}

type newUserList []User 

func (I newUserList) Len() int { 
    return len(I) 
} 

func (I newUserList) Less(i, j int) bool { 
    return stringConvertTime(I[i].ApplyTime) > stringConvertTime(I[j].ApplyTime) 
} 

func (I newUserList) Swap(i, j int) { 
    I[i], I[j] = I[j], I[i] 
} 

例如对user_list进行排序:
TestData["license_detail"] = `{
                "user_list":[
                        {
                                "applicant_guid":"guid",
                                "apply_time":"2018-03-06 20:44:51",
                                "used_license":"10",
                                "applicant":"tim1"
                        },
                        {
                                "applicant_guid":"guid11",
                                "apply_time":"2018-03-07 20:44:33",
                                "used_license":"10",
                                "applicant":"tim2"
                        },
                        {
                                "applicant_guid":"guid_tin",
                                "apply_time":"2018-03-05 20:44:33",
                                "used_license":"10",
                                "applicant":"tim3"
                        }
                ]
        }`

var users []User
遍历user_list获取到users
sort.Sort(newUserList(users))进行排序可以得到正确排序