使用commons fileupload的零碎笔记

1，form里的属性值不能用request.getParameter()获取了，而url里的queryString可以。
2,  获取form里的属性值的代码

                    String formname = fi.getFieldName();// 获取form中的名字
                    String formcontent = fi.getString();
                    if (formname.equals("id")) {
                        id = formcontent;
                    } else if (formname.equals("title")) {
                        title = formcontent;
                    } else if (formname.equals("memo")) {
                        memo = formcontent;
                    }
                

3, form里的file控件的name不能为空。
4，上传大文件(190多M)时报异常
org.apache.commons.fileupload.FileUploadException:   Processing   of   multipart/form-data   request   failed.   EOF   after   reading   only:   "3567789 "   of:   "203323339 "   promised   bytes,   out  of   which   at   least:   "0 "   were   already   buffered
http://forums.bea.com/thread.jspa?threadID=200033356
http://dev2dev.bea.com.cn/bbs/thread.jspa?forumID=121&threadID=20060&start=0&tstart=0
http://thisisxy.blogcn.com/diary,204014352.shtml
http://www.80diy.com/home/20050527/17/4040711.html

5，
org.apache.commons.fileupload.FileUploadException: Processing of multipart/form-data request failed. Read timed out
HTTP活动超时限制的时间太短 HTTP Keep-Alive Timeout.

6,
http://eastpoint.iteye.com/blog/99084
http://topic.csdn.net/u/20080131/13/649c57c7-204e-4bb6-9b09-49cca39f00b8.html
http://blog.niwota.com/nb/chenchuang?cat_self_id=291075

分享到：

web网址 | 我关注的开源ERP,CRM

• 2007-08-27 11:58
• 浏览 2039
• 评论(0)
• 查看更多