oracle去重(面试)

现有Oracle中数据如下：

 

第一种方法：

使用多层嵌套查询，这种方法会多次扫描表

1.通过emp_no进行分组，查询出每个分组中最大的ID

select max(id) from employee t group by t.emp_no having count(1) > 1;

 

2.删除重复记录，但这样只能删除具有2条的重复记录。如果具有2条以上的重复记录，则无法删除

delete from employee t where t.id in (select max(t1.id) from employee t1 group by t1.emp_no having count(1) > 1)

 

优化如下：

①获取有重复记录的员工记录

select t1.* from employee t1 where t1.emp_no in (select t.emp_no  from employee t group by t.emp_no having count(1) > 1) 

②从重复记录的员工号中获取最小的id

select min(t2.id) from (select t1.* from employee t1 where t1.emp_no in (select t.emp_no  from employee t group by t.emp_no having count(1) > 1)) t2 group by t2.emp_no

③将①和②结合查询出多余的重复记录

select t1.* from employee t1 where t1.emp_no in (select t.emp_no  from employee t group by t.emp_no having count(1) > 1) 

and t1.id not in (

select min(t2.id) from (select t1.* from employee t1 where t1.emp_no in (select t.emp_no  from employee t group by t.emp_no having count(1) > 1)) t2 group by t2.emp_no

)

④删除重复记录

delete from employee t3  where t3.id in (

    select t1.* from employee t1 where t1.emp_no in (select t.emp_no  from employee t group by t.emp_no having count(1) > 1) 

    and not in (

         select min(t2.id) from (select t1.* from employee t1 where t1.emp_no in (select t.emp_no  from employee t group by t.emp_no having count(1) > 1)) t2 group by t2.emp_no

    )

)

 

 

 

第二种方法(推荐)：

使用row_number()  over()

1.先通过emp_no进行分组，然后通过sal进行排序，得到序列seq

select t.* , row_number() over(partition by t.emp_no order by t.sal desc)  seq from employee t

 

 

2.获取每个分组中序列seq大于1记录的id

select t1.id
  from (select t.*,
               row_number() over(partition by t.emp_no order by t.sal desc) seq
          from employee t) t1
 where t1.seq > 1

3.删除重复记录

delete from employee t2
 where t2.id in (select t1.id
                   from (select t.*,
                                row_number() over(partition by t.emp_no order by t.sal desc) seq
                           from employee t) t1
                  where t1.seq > 1)