HashMap与ConcurrentHashMap的区别

        从JDK1.2起，就有了HashMap，正如前一篇文章所说，HashMap不是线程安全的，因此多线程操作时需要格外小心。

        在JDK1.5中，伟大的Doug Lea给我们带来了concurrent包，从此Map也有安全的了。

        ConcurrentHashMap具体是怎么实现线程安全的呢，肯定不可能是每个方法加synchronized，那样就变成了HashTable。

        从ConcurrentHashMap代码中可以看出，它引入了一个“分段锁”的概念，具体可以理解为把一个大的Map拆分成N个小的HashTable，根据key.hashCode()来决定把key放到哪个HashTable中。

        在ConcurrentHashMap中，就是把Map分成了N个Segment，put和get的时候，都是现根据key.hashCode()算出放到哪个Segment中：

    /**
     * Maps the specified key to the specified value in this table.
     * Neither the key nor the value can be null.
     *
     * <p> The value can be retrieved by calling the <tt>get</tt> method
     * with a key that is equal to the original key.
     *
     * @param key key with which the specified value is to be associated
     * @param value value to be associated with the specified key
     * @return the previous value associated with <tt>key</tt>, or
     *         <tt>null</tt> if there was no mapping for <tt>key</tt>
     * @throws NullPointerException if the specified key or value is null
     */
    @SuppressWarnings("unchecked")
    public V put(K key, V value) {
        Segment<K,V> s;
        if (value == null)
            throw new NullPointerException();
        int hash = hash(key);
        int j = (hash >>> segmentShift) & segmentMask;
        if ((s = (Segment<K,V>)UNSAFE.getObject          // nonvolatile; recheck
             (segments, (j << SSHIFT) + SBASE)) == null) //  in ensureSegment
            s = ensureSegment(j);
        return s.put(key, hash, value, false);
    }

    /**
     * Returns the value to which the specified key is mapped,
     * or {@code null} if this map contains no mapping for the key.
     *
     * <p>More formally, if this map contains a mapping from a key
     * {@code k} to a value {@code v} such that {@code key.equals(k)},
     * then this method returns {@code v}; otherwise it returns
     * {@code null}.  (There can be at most one such mapping.)
     *
     * @throws NullPointerException if the specified key is null
     */
    public V get(Object key) {
        Segment<K,V> s; // manually integrate access methods to reduce overhead
        HashEntry<K,V>[] tab;
        int h = hash(key);
        long u = (((h >>> segmentShift) & segmentMask) << SSHIFT) + SBASE;
        if ((s = (Segment<K,V>)UNSAFE.getObjectVolatile(segments, u)) != null &&
            (tab = s.table) != null) {
            for (HashEntry<K,V> e = (HashEntry<K,V>) UNSAFE.getObjectVolatile
                     (tab, ((long)(((tab.length - 1) & h)) << TSHIFT) + TBASE);
                 e != null; e = e.next) {
                K k;
                if ((k = e.key) == key || (e.hash == h && key.equals(k)))
                    return e.value;
            }
        }
        return null;
    }

        如果key.hashCode()相同，表示它们将会放在同一个Segment上，如果是并发放入的话，可能会阻塞直到前面的put动作完成。

        Segment.put方法：

        Segment.remove方法：

参考文章：http://blog.csdn.net/xuefeng0707/article/details/40834595