python发送email

第一种方法： 

# -*- coding: utf-8 -*-

import email
import mimetypes
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
from email.MIMEImage import MIMEImage
import smtplib

def sendEmail(authInfo, fromAdd, toAdd, subject, plainText, htmlText):

        strFrom = fromAdd
        strTo = ', '.join(toAdd)

        server = authInfo.get('server')
        user = authInfo.get('user')
        passwd = authInfo.get('password')

        if not (server and user and passwd) :
                print 'incomplete login info, exit now'
                return

        # 设定root信息
        msgRoot = MIMEMultipart('related')
        msgRoot['Subject'] = subject
        msgRoot['From'] = strFrom
        msgRoot['To'] = strTo
        msgRoot.preamble = 'This is a multi-part message in MIME format.'

        # Encapsulate the plain and HTML versions of the message body in an
        # 'alternative' part, so message agents can decide which they want to display.
        msgAlternative = MIMEMultipart('alternative')
        msgRoot.attach(msgAlternative)

        #设定纯文本信息
#        msgText = MIMEText(plainText, 'plain', 'utf-8')
#        msgAlternative.attach(msgText)

        #设定HTML信息
        msgText = MIMEText(htmlText, 'html', 'utf-8')
        msgAlternative.attach(msgText)

       #设定内置图片信息
#        fp = open('test.jpg', 'rb')
#        msgImage = MIMEImage(fp.read())
#        fp.close()
#        msgImage.add_header('Content-ID', '<image1>')
#        msgRoot.attach(msgImage)

       #发送邮件
        smtp = smtplib.SMTP()
       #设定调试级别，依情况而定
        smtp.set_debuglevel(1)
        smtp.connect(server)
        smtp.login(user, passwd)
        smtp.sendmail(strFrom, strTo, msgRoot.as_string())
#        smtp.sendmail(strFrom, strTo, msgRoot.as_string())
        smtp.quit()
        return

if __name__ == '__main__' :
        authInfo = {}
        authInfo['server'] = 'smtp.***.cn'
        authInfo['user'] = '***@***.cn'
        authInfo['password'] = '***'
        fromAdd = '***@***.cn'
        toAdd = ['***@163.com', '***@gamil.com']
        subject = 'title'
        plainText = '这里是普通文本'
        htmlText = '<B>HTML文本</B>'
        sendEmail(authInfo, fromAdd, toAdd, subject, plainText, htmlText)

第二种方法： 

#coding=utf-8

import smtplib,email,sys
from email.Message import Message


smtpserver='smtp.***.cn'
smtpuser='***@***.cn'
smtppass='***'
smtpport='25'

def connect():
    "connect to smtp server and return a smtplib.SMTP instance object"
    server=smtplib.SMTP(smtpserver,smtpport)
    server.ehlo()
    server.login(smtpuser,smtppass)
    return server

def sendmessage(server,to,subj,content):
    "using server send a email"
    msg = Message()
    msg['Mime-Version']='1.0'
    msg['From']    = smtpuser
    msg['To']      = to
    msg['Subject'] = subj
    msg['Date']    = email.Utils.formatdate()          # curr datetime, rfc2822
    msg.set_payload(content)
    try:
        failed = server.sendmail(smtpuser,to,str(msg))   # may also raise exc
    except Exception ,ex:
        print Exception,ex
        print 'Error - send failed'
    else:
        print "send success!"

if __name__=="__main__":
    #frm=raw_input('From? ').strip()
#    to=raw_input('To? ').strip()
#    subj=raw_input('Subj? ').strip()
    to='***@***.com'
    subj='title1111'
    print 'Type message text, end with line="."'
    text = 'content'
#    while True:
#        line = sys.stdin.readline()
#        if line == '. ': break
#        text += line
    server=connect()
    sendmessage(server,to,subj,text)

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第一种方法 line 56 有个bug：收件人为多人时，只有第一个收件人能收到。

smtp.sendmail(strFrom, strTo, msgRoot.as_string())

改为

smtp.sendmail(strFrom, toAdd, msgRoot.as_string())

即可