Given a binary tree, return all root-to-leaf paths.
For example, given the following binary tree:
1 / \ 2 3 \ 5
All root-to-leaf paths are:
["1->2->5", "1->3"]
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { List<String> res = new ArrayList<>(); public List<String> binaryTreePaths(TreeNode root) { if (root != null) { findPaths(root, String.valueOf(root.val)); } return res; } private void findPaths(TreeNode root, String valueOf) { // TODO Auto-generated method stub if (root.left == null && root.right == null) { res.add(valueOf); } if (root.left != null) { findPaths(root.left, valueOf + "->" + root.left.val); } if (root.right != null) { findPaths(root.right, valueOf + "->" + root.right.val); } } }
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