package leetcode;
/**
* <pre>
* Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
*
* For example:
* Given the below binary tree and sum = 22,
* 5
* / \
* 4 8
* / / \
* 11 13 4
* / \ \
* 7 2 1
* return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
* </pre>
* */
public class PathSum {
public class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode(int x) {
val = x;
}
}
public class Solution {
public boolean hasPathSum(TreeNode root, int sum) {
if (root == null)
return false;
if (root.left == null && root.right == null)
return root.val == sum;
return hasPathSum(root.left, sum - root.val)
|| hasPathSum(root.right, sum - root.val);
}
}
}
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