Javascript的各种排序算法实现,转自某位牛人，具体地址已不记得

http://www.cnblogs.com/iceidea/archive/2011/10/22/2221195.html

 

// ---------- 一些排序算法
var Sort = {}
Sort.prototype = {
      // 利用sort进行排序 
       systemSort:function(array){ 
          return array.sort(function(a, b){ 
              return a - b; 
          }); 
      },
     
      // 冒泡排序 
      bubbleSort:function(array){ 
          var i = 0, len = array.length, 
              j, d; 
          for(; i<len; i++){ 
              for(j=0; j<len; j++){ 
                  if(array[i] < array[j]){ 
                      d = array[j]; 
                      array[j] = array[i]; 
                      array[i] = d; 
                  } 
              } 
          } 
          return array; 
      },
     
      // 快速排序 
      quickSort:function(array){ 
          //var array = [8,4,6,2,7,9,3,5,74,5]; 
          //var array =[0,1,2,44,4,324,5,65,6,6,34,4,5,6,2,43,5,6,62,43,5,1,4,51,56,76,7,7,2,1,45,4,6,7]; 
          var i = 0; 
          var j = array.length - 1; 
          var Sort = function(i, j){ 
              // 结束条件 
              if(i == j ){ return };
              var key = array[i]; 
              var tempi = i; // 记录开始位置 
              var tempj = j; // 记录结束位置 
             
              while(j > i){ 
                  // j <<-------------- 向前查找 
                  if(array[j] >= key){ 
                      j--; 
                  }else{ 
                      array[i] = array[j] 
                      //i++ ------------>>向后查找 
                      while(j > ++i){ 
                          if(array[i] > key){ 
                              array[j] = array[i]; 
                              break; 
                          } 
                      } 
                  } 
              }
              // 如果第一个取出的 key 是最小的数 
              if(tempi == i){ 
                  Sort(++i, tempj); 
                  return ; 
              }
              // 最后一个空位留给 key 
              array[i] = key; 
              // 递归 
              Sort(tempi, i); 
              Sort(j, tempj); 
          } 
          Sort(i, j);
          return array; 
      }, 
       
      // 插入排序 
      insertSort:function(array){ 
          // http://baike.baidu.com/image/d57e99942da24e5dd21b7080 
          // http://baike.baidu.com/view/396887.htm 
          // var array = [0,1,2,44,4,324,5,65,6,6,34,4,5,6,2,43,5,6,62,43,5,1,4,51,56,76,7,7,2,1,45,4,6,7]; 
          var i = 1, j, temp, key, len = array.length;
          for(; i < len; i++){ 
              temp = j = i; 
              key = array[j]; 
              while(--j > -1){ 
                  if(array[j] > key){ 
                      array[j+1] = array[j]; 
                  }else{
                      break;
                  }
              }
              array[j+1] = key; 
          }
          return array; 
      }, 
       
      // 希尔排序 
      //Jun.array.shellSort(Jun.array.df(10000)); 
      shellSort:function(array){ 
          // http://zh.wikipedia.org/zh/%E5%B8%8C%E5%B0%94%E6%8E%92%E5%BA%8F 
          // var array = [13,14,94,33,82,25,59,94,65,23,45,27,73,25,39,10];
          // var tempArr = [1750, 701, 301, 132, 57, 23, 10, 4, 1];  
          // reverse() 在维基上看到这个最优的步长 较小数组 
          var tempArr = [1031612713, 217378076, 45806244, 9651787, 2034035, 428481, 90358, 19001, 4025, 836, 182, 34, 9, 1] 
              //针对大数组的步长选择 
          var i = 0; 
          var tempArrtempArrLength = tempArr.length; 
          var len = array.length; 
          var len2 =  parseInt(len/2); 
           
          for(;i < tempArrLength; i++){ 
              if(tempArr[i] > len2){ 
                  continue; 
              }
              tempSort(tempArr[i]); 
          }
          // 排序一个步长 
          function tempSort(temp){ 
              //console.log(temp) 使用的步长统计 
              var i = 0, j = 0, f, tem, key; 
              var tempLen = len%temp > 0 ?  parseInt(len/temp) + 1 : len/temp;  
             
              for(;i < temp; i++){// 依次循环列 
  
                  for(j=1;/*j < tempLen && */temp * j + i < len; j++){
                        //依次循环每列的每行 
                      tem = f = temp * j + i; 
                      key = array[f]; 
  
                      while((tem-=temp) >= 0){ 
                            // 依次向上查找
                          if(array[tem] > key){
                              array[tem+temp] = array[tem];
                          }else{
                              break;
                          }
                      }
                      array[tem + temp ] = key;
                  }
              }
          }
          return array;
      }
}