如何获得程序的初始化参数

通过application对象获取程序的初始化参数

 

web.xml

 

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" 
	xmlns="http://java.sun.com/xml/ns/j2ee" 
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
	xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
	http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
  <context-param>
  	<param-name>url</param-name>
  	<param-value>localhost:8080/</param-value>
  </context-param>
  <context-param>
  	<param-name>name</param-name>
  	<param-value>root</param-value>
  </context-param>
  <context-param>
  	<param-name>password</param-name>
  	<param-value>1</param-value>
  </context-param>
</web-app>

jsp页面输出

 

<%
  			String url = application.getInitParameter("url");//获取初始化参数，与web.xml中的内容相对应
  			String name = application.getInitParameter("name");
  			String password = application.getInitParameter("password");
  			out.println(url+"<br>");
  			out.println(name+"<br>");
  			out.println(password);
  		
  		%>