`
编程足球
  • 浏览: 257089 次
  • 性别: Icon_minigender_1
  • 来自: 福州
社区版块
存档分类
最新评论

java 源码解析--LinkedList

    博客分类:
  • java
阅读更多
LinkedList




1.看源码前应该知道的知识点
/**
 * 
 */
package com.study.collection;

import java.util.NoSuchElementException;
/**   
 * 
 * @className :LinkedListLearn  
 * @package : com.study.collection 
 * @Description :Linked源码学习必备知识   
 * @author:lgf   
 * @date :2012 三月 13  10:38:11          
 * @version : 1.0
 */
public class LinkedListLearn<E> {
	// 结构
	// 本身就是一个双向链表来实现LinkedList过程
	private transient Entry<E> header = new Entry<E>(null, null, null);
    private static class Entry<E> {
    	E element;
    	Entry<E> next;
    	Entry<E> previous;
    	Entry(E element, Entry<E> next, Entry<E> previous) {
    	    this.element = element;
    	    this.next = next;
    	    this.previous = previous;
    	}
    }
    // List 大小
    private transient int size = 0;
    
    /**
     * @author lgf
     * @Description: 删除指定节点的方法
     * @CreateDate 2012 三月 13 10:48:33
     * @lastModified 2012 三月 13 10:48:33
     * @version 1.0
     * @param element 要删除的几点
     * @return
     */
    @SuppressWarnings("unused")
	private E remove(Entry<E> element) {
    	// 如果e就是header未默认头节点。则抛出异常,无法删除
		if (element == header)
		    throw new NoSuchElementException();
		
		// 保存要删除节点的信息
		E result = element.element;
		// 前节点连接上后几点
		element.previous.next = element.next;
		// 后节点连接上前节点
		element.next.previous = element.previous;
		// 移除指定点设置null
	    element.next = element.previous = null;
	    element.element = null;
		size--;
		return result;
    }
    
    /**
     * @author lgf
     * @Description: 在指定节点前插入新节点
     * @CreateDate 2012 三月 13 11:21:58
     * @lastModified 2012 三月 13 11:21:58
     * @version 1.0
     * @param e 要插入的元素
     * @param entry 要插入节点的前面
     * @return
     */
    @SuppressWarnings("unused")
	private Entry<E> addBefore(E e, Entry<E> entry) {
    	// 新建一个节点,同时设置其后面和前面的节点信息
    	Entry<E> newEntry = new Entry<E>(e, entry, entry.previous);
    	// 插入到新位置
    	newEntry.previous.next = newEntry;
    	newEntry.next.previous = newEntry;
    	size++;
    	return newEntry;
    }
    
    /**
     * @author lgf
     * @Description: 对linkedList进行遍历
     * @CreateDate 2012 三月 13 11:40:11
     * @lastModified 2012 三月 13 11:40:11
     * @version 1.0
     */
    public void foreach(){
    	for (Entry<E> e = header.next; e != header; e = e.next) {
    		//TODO:
        }
    }
    
    /**
     * @author lgf
     * @Description: 获得指定下标index的值
     * @CreateDate 2012 三月 13 11:42:39
     * @lastModified 2012 三月 13 11:42:39
     * @version 1.0
     * @param index
     * @return
     */
    private Entry<E> entry(int index) {
        if (index < 0 || index >= size)
            throw new IndexOutOfBoundsException("Index: " + index + ", Size: "+size);
        Entry<E> e = header;
        // 判断index 于 size/2 的大小关系
        if (index < (size >> 1)) {// 如果index在偏后,则从头开始完后遍历
            for (int i = 0; i <= index; i++)
                e = e.next;
        } else { // 否则index偏前,则从头向前开始遍历
            for (int i = size; i > index; i--)
            	e = e.previous;
        }
        return e;
    }
    
	public static void main(String[] args) {
		
	}
}



2.源码
package java.util;
public class LinkedList<E>
    extends AbstractSequentialList<E>
    implements List<E>, Deque<E>, Cloneable, java.io.Serializable
{
    private transient Entry<E> header = new Entry<E>(null, null, null);
    private transient int size = 0;

    /**
     * 空构造函数,前后互联
     */
    public LinkedList() {
        header.next = header.previous = header;
    }

    /**
     *	构造一个包含指定 collection 中的元素的列表,
	 *	这些元素按其 collection 的迭代器返回的顺序排列
     * @param  c 要将其元素放入此列表的 collection 
     * @throws NullPointerException 如果指定的 collection 为 null
     */
    public LinkedList(Collection<? extends E> c) {
		this();
		addAll(c);
    }

    /**
     * 获得第一个元素的信息
     * @return 此列表的第一个元素 
     * @throws NoSuchElementException 如果此列表为空
     */
    public E getFirst() {
		if (size==0)
			throw new NoSuchElementException();
		return header.next.element;
    }

    /**
     * Returns the last element in this list.
     *
     * @return the last element in this list
     * @throws NoSuchElementException if this list is empty
     */
    public E getLast()  {
		if (size==0)
			throw new NoSuchElementException();
		return header.previous.element;
    }

    /**
     * Removes and returns the first element from this list.
     * 移除第一个
     * @return the first element from this list
     * @throws NoSuchElementException if this list is empty
     */
    public E removeFirst() {
		return remove(header.next);
    }

    /**
     * Removes and returns the last element from this list.
     * 移除最后一个
     * @return the last element from this list
     * @throws NoSuchElementException if this list is empty
     */
    public E removeLast() {
		return remove(header.previous);
    }

    /**
     * Inserts the specified element at the beginning of this list.
     * 添加第一个
     * @param e the element to add
     */
    public void addFirst(E e) {
	addBefore(e, header.next);
    }

    /**
     * Appends the specified element to the end of this list.
     * 添加最后一个
     * <p>This method is equivalent to {@link #add}.
     *
     * @param e the element to add
     */
    public void addLast(E e) {
		addBefore(e, header);
    }

    /**
     * Returns true if this list contains the specified element.
     * More formally, returns trueif and only if this list contains
     * at least one element <tt>e</tt> such that
     * (o==null&nbsp;?&nbsp;e==null&nbsp;:&nbsp;o.equals(e))
     * 判断某对象是否存在,存在则true
     * @param o element whose presence in this list is to be tested
     * @return <tt>true</tt> if this list contains the specified element
     */
    public boolean contains(Object o) {
        return indexOf(o) != -1;
    }

    /**
     * Returns the number of elements in this list.
     * 大小
     * @return the number of elements in this list
     */
    public int size() {
		return size;
    }

    /**
     * Appends the specified element to the end of this list.
     * 添加一个元素,等同于addLast(E e)
     * <p>This method is equivalent to {@link #addLast}.
     *
     * @param e element to be appended to this list
     * @return <tt>true</tt> (as specified by {@link Collection#add})
     */
    public boolean add(E e) {
		addBefore(e, header);
        return true;
    }

    /**
     * Removes the first occurrence of the specified element from this list,
     * if it is present.  If this list does not contain the element, it is
     * unchanged.  More formally, removes the element with the lowest index
     * <tt>i</tt> such that
     * <tt>(o==null&nbsp;?&nbsp;get(i)==null&nbsp;:&nbsp;o.equals(get(i)))</tt>
     * (if such an element exists).  Returns <tt>true</tt> if this list
     * contained the specified element (or equivalently, if this list
     * changed as a result of the call).
     * 从此列表中移除首次出现的指定元素(如果存在)。如果列表不包含该元素,则不作更改。
	 * 注意是首次出现的元素,null则查找首次出现的null
     * @param o element to be removed from this list, if present
     * @return <tt>true</tt> if this list contained the specified element
     */
    public boolean remove(Object o) {
        if (o==null) { //元素为null
            for (Entry<E> e = header.next; e != header; e = e.next) {
                if (e.element==null) {
                    remove(e);
                    return true;
                }
            }
        } else { // 非null
            for (Entry<E> e = header.next; e != header; e = e.next) {
                if (o.equals(e.element)) {
                    remove(e);
                    return true;
                }
            }
        }
        return false;
    }

    /**
     * Appends all of the elements in the specified collection to the end of
     * this list, in the order that they are returned by the specified
     * collection's iterator.  The behavior of this operation is undefined if
     * the specified collection is modified while the operation is in
     * progress.  (Note that this will occur if the specified collection is
     * this list, and it's nonempty.)
     * 加指定 collection 中的所有元素到此列表的结尾,
	 * 顺序是指定 collection 的迭代器返回这些元素的顺序 c.toArray()
     * @param c collection containing elements to be added to this list
     * @return <tt>true</tt> if this list changed as a result of the call
     * @throws NullPointerException if the specified collection is null
     */
    public boolean addAll(Collection<? extends E> c) {
        return addAll(size, c);
    }

    /**
     * Inserts all of the elements in the specified collection into this
     * list, starting at the specified position.  Shifts the element
     * currently at that position (if any) and any subsequent elements to
     * the right (increases their indices).  The new elements will appear
     * in the list in the order that they are returned by the
     * specified collection's iterator.
     * 将指定 collection 中的所有元素从指定位置开始插入此列表。
	 * 移动当前在该位置上的元素(如果有),所有后续元素都向右移(增加其索引)。
	 * 新元素将按由指定 collection 的迭代器返回的顺序在列表中显示。 
     * @param index index at which to insert the first element
     *              from the specified collection
     * @param c collection containing elements to be added to this list
     * @return <tt>true</tt> if this list changed as a result of the call
     * @throws IndexOutOfBoundsException {@inheritDoc}
     * @throws NullPointerException if the specified collection is null
     */
    public boolean addAll(int index, Collection<? extends E> c) {
        if (index < 0 || index > size)
            throw new IndexOutOfBoundsException("Index: "+index+", Size: "+size);
        Object[] a = c.toArray();
        int numNew = a.length;
        if (numNew==0)
            return false;
		modCount++;
		
		// 要插入节点的位置
        Entry<E> successor = (index==size ? header : entry(index));
		//要插入节点位置前一个
        Entry<E> predecessor = successor.previous;
		
		// 一个个插入到列表中
		for (int i=0; i<numNew; i++) {
            Entry<E> e = new Entry<E>((E)a[i], successor, predecessor);
            predecessor.next = e;
            predecessor = e;
        }
        successor.previous = predecessor;

        size += numNew;
        return true;
    }

    /**
     * Removes all of the elements from this list.
     */
    public void clear() {
        Entry<E> e = header.next;
        while (e != header) {
            Entry<E> next = e.next;
            e.next = e.previous = null;
            e.element = null;
            e = next;
        }
        header.next = header.previous = header;
        size = 0;
		modCount++;
    }


    // Positional Access Operations

    /**
     * Returns the element at the specified position in this list.
     *
     * @param index index of the element to return
     * @return the element at the specified position in this list
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public E get(int index) {
        return entry(index).element;
    }

    /**
     * Replaces the element at the specified position in this list with the
     * specified element.
     * 设置值
     * @param index index of the element to replace
     * @param element element to be stored at the specified position
     * @return the element previously at the specified position
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public E set(int index, E element) {
        Entry<E> e = entry(index);
        E oldVal = e.element;
        e.element = element;
        return oldVal;
    }

    /**
     * Inserts the specified element at the specified position in this list.
     * Shifts the element currently at that position (if any) and any
     * subsequent elements to the right (adds one to their indices).
     * 在指定位置前插入值
     * @param index index at which the specified element is to be inserted
     * @param element element to be inserted
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public void add(int index, E element) {
        addBefore(element, (index==size ? header : entry(index)));
    }

    /**
     * Removes the element at the specified position in this list.  Shifts any
     * subsequent elements to the left (subtracts one from their indices).
     * Returns the element that was removed from the list.
     * 移除指定位置的值
     * @param index the index of the element to be removed
     * @return the element previously at the specified position
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public E remove(int index) {
        return remove(entry(index));
    }

    /**
     * Returns the indexed entry.
     */
    private Entry<E> entry(int index) {
        if (index < 0 || index >= size)
            throw new IndexOutOfBoundsException("Index: "+index+
                                                ", Size: "+size);
        Entry<E> e = header;
        if (index < (size >> 1)) {
            for (int i = 0; i <= index; i++)
                e = e.next;
        } else {
            for (int i = size; i > index; i--)
                e = e.previous;
        }
        return e;
    }


    // Search Operations

    /**
     * Returns the index of the first occurrence of the specified element
     * in this list, or -1 if this list does not contain the element.
     * More formally, returns the lowest index <tt>i</tt> such that
     * <tt>(o==null&nbsp;?&nbsp;get(i)==null&nbsp;:&nbsp;o.equals(get(i)))</tt>,
     * or -1 if there is no such index.
     * 查找指定对象的位置下表
	 * 返回此列表中最后出现的指定元素的索引,如果此列表中不包含该元素,则返回 -1。
     * @param o element to search for
     * @return the index of the first occurrence of the specified element in
     *         this list, or -1 if this list does not contain the element
     */
    public int indexOf(Object o) {
        int index = 0;
        if (o==null) {
            for (Entry e = header.next; e != header; e = e.next) {
                if (e.element==null)
                    return index;
                index++;
            }
        } else {
            for (Entry e = header.next; e != header; e = e.next) {
                if (o.equals(e.element))
                    return index;
                index++;
            }
        }
        return -1;
    }

    /**
     * Returns the index of the last occurrence of the specified element
     * in this list, or -1 if this list does not contain the element.
     * More formally, returns the highest index <tt>i</tt> such that
     * <tt>(o==null&nbsp;?&nbsp;get(i)==null&nbsp;:&nbsp;o.equals(get(i)))</tt>,
     * or -1 if there is no such index.
     * 返回此列表中最后出现的指定元素的索引,如果此列表中不包含该元素,则返回 -1。
     * @param o element to search for
     * @return the index of the last occurrence of the specified element in
     *         this list, or -1 if this list does not contain the element
     */
    public int lastIndexOf(Object o) {
        int index = size;
        if (o==null) {
            for (Entry e = header.previous; e != header; e = e.previous) {
                index--;
                if (e.element==null)
                    return index;
            }
        } else {
            for (Entry e = header.previous; e != header; e = e.previous) {
                index--;
                if (o.equals(e.element))
                    return index;
            }
        }
        return -1;
    }

    // Queue operations.

    /**
     * Retrieves, but does not remove, the head (first element) of this list.
	 * 获取但不移除此列表的头(第一个元素)。 
     * @return the head of this list, or <tt>null</tt> if this list is empty
     * @since 1.5
     */
    public E peek() {
        if (size==0)
            return null;
        return getFirst();
    }

    /**
     * Retrieves, but does not remove, the head (first element) of this list.
     * @return the head of this list
     * @throws NoSuchElementException if this list is empty
     * @since 1.5
     */
    public E element() {
        return getFirst();
    }

    /**
     * Retrieves and removes the head (first element) of this list
	 * 此列表的头,如果此列表为空,则返回 null
     * @return the head of this list, or <tt>null</tt> if this list is empty
     * @since 1.5
     */
    public E poll() {
        if (size==0)
            return null;
        return removeFirst();
    }

    /**
     * Retrieves and removes the head (first element) of this list.
     *
     * @return the head of this list
     * @throws NoSuchElementException if this list is empty
     * @since 1.5
     */
    public E remove() {
        return removeFirst();
    }

    /**
     * Adds the specified element as the tail (last element) of this list.
     *
     * @param e the element to add
     * @return <tt>true</tt> (as specified by {@link Queue#offer})
     * @since 1.5
     */
    public boolean offer(E e) {
        return add(e);
    }

    // Deque operations
    /**
     * Inserts the specified element at the front of this list.
     *
     * @param e the element to insert
     * @return <tt>true</tt> (as specified by {@link Deque#offerFirst})
     * @since 1.6
     */
    public boolean offerFirst(E e) {
        addFirst(e);
        return true;
    }

    /**
     * Inserts the specified element at the end of this list.
     *
     * @param e the element to insert
     * @return <tt>true</tt> (as specified by {@link Deque#offerLast})
     * @since 1.6
     */
    public boolean offerLast(E e) {
        addLast(e);
        return true;
    }

    /**
     * Retrieves, but does not remove, the first element of this list,
     * or returns <tt>null</tt> if this list is empty.
     *
     * @return the first element of this list, or <tt>null</tt>
     *         if this list is empty
     * @since 1.6
     */
    public E peekFirst() {
        if (size==0)
            return null;
        return getFirst();
    }

    /**
     * Retrieves, but does not remove, the last element of this list,
     * or returns <tt>null</tt> if this list is empty.
     *
     * @return the last element of this list, or <tt>null</tt>
     *         if this list is empty
     * @since 1.6
     */
    public E peekLast() {
        if (size==0)
            return null;
        return getLast();
    }

    /**
     * Retrieves and removes the first element of this list,
     * or returns <tt>null</tt> if this list is empty.
     *
     * @return the first element of this list, or <tt>null</tt> if
     *     this list is empty
     * @since 1.6
     */
    public E pollFirst() {
        if (size==0)
            return null;
        return removeFirst();
    }

    /**
     * Retrieves and removes the last element of this list,
     * or returns <tt>null</tt> if this list is empty.
     *
     * @return the last element of this list, or <tt>null</tt> if
     *     this list is empty
     * @since 1.6
     */
    public E pollLast() {
        if (size==0)
            return null;
        return removeLast();
    }

    /**
     * Pushes an element onto the stack represented by this list.  In other
     * words, inserts the element at the front of this list.
     *
     * <p>This method is equivalent to {@link #addFirst}.
     *
     * @param e the element to push
     * @since 1.6
     */
    public void push(E e) {
        addFirst(e);
    }

    /**
     * Pops an element from the stack represented by this list.  In other
     * words, removes and returns the first element of this list.
     *
     * <p>This method is equivalent to {@link #removeFirst()}.
     *
     * @return the element at the front of this list (which is the top
     *         of the stack represented by this list)
     * @throws NoSuchElementException if this list is empty
     * @since 1.6
     */
    public E pop() {
        return removeFirst();
    }

    /**
     * Removes the first occurrence of the specified element in this
     * list (when traversing the list from head to tail).  If the list
     * does not contain the element, it is unchanged.
     *
     * @param o element to be removed from this list, if present
     * @return <tt>true</tt> if the list contained the specified element
     * @since 1.6
     */
    public boolean removeFirstOccurrence(Object o) {
        return remove(o);
    }

    /**
     * Removes the last occurrence of the specified element in this
     * list (when traversing the list from head to tail).  If the list
     * does not contain the element, it is unchanged.
     * 从此列表中移除第一次出现的指定元素(从头部到尾部遍历列表时)。
	 * 如果列表不包含该元素,则不作更改。 
     * @param o element to be removed from this list, if present
     * @return <tt>true</tt> if the list contained the specified element
     * @since 1.6
     */
    public boolean removeLastOccurrence(Object o) {
        if (o==null) {
            for (Entry<E> e = header.previous; e != header; e = e.previous) {
                if (e.element==null) {
                    remove(e);
                    return true;
                }
            }
        } else {
            for (Entry<E> e = header.previous; e != header; e = e.previous) {
                if (o.equals(e.element)) {
                    remove(e);
                    return true;
                }
            }
        }
        return false;
    }

    /**
     * Returns a list-iterator of the elements in this list (in proper
     * sequence), starting at the specified position in the list.
     * Obeys the general contract of <tt>List.listIterator(int)</tt>.<p>
     *
     * The list-iterator is <i>fail-fast</i>: if the list is structurally
     * modified at any time after the Iterator is created, in any way except
     * through the list-iterator's own <tt>remove</tt> or <tt>add</tt>
     * methods, the list-iterator will throw a
     * <tt>ConcurrentModificationException</tt>.  Thus, in the face of
     * concurrent modification, the iterator fails quickly and cleanly, rather
     * than risking arbitrary, non-deterministic behavior at an undetermined
     * time in the future.
     *
     * @param index index of the first element to be returned from the
     *              list-iterator (by a call to <tt>next</tt>)
     * @return a ListIterator of the elements in this list (in proper
     *         sequence), starting at the specified position in the list
     * @throws IndexOutOfBoundsException {@inheritDoc}
     * @see List#listIterator(int)
     */
    public ListIterator<E> listIterator(int index) {
		return new ListItr(index);
    }

    private class ListItr implements ListIterator<E> {
		private Entry<E> lastReturned = header;
		private Entry<E> next;
		private int nextIndex;
		private int expectedModCount = modCount;

		ListItr(int index) {
			if (index < 0 || index > size)
			throw new IndexOutOfBoundsException("Index: "+index+
								", Size: "+size);
			if (index < (size >> 1)) {
				next = header.next;
				for (nextIndex=0; nextIndex<index; nextIndex++)
					next = next.next;
			} else {
				next = header;
				for (nextIndex=size; nextIndex>index; nextIndex--)
					next = next.previous;
			}
		}

		public boolean hasNext() {
			return nextIndex != size;
		}

		public E next() {
			checkForComodification();
			if (nextIndex == size)
			throw new NoSuchElementException();

			lastReturned = next;
			next = next.next;
			nextIndex++;
			return lastReturned.element;
		}

		public boolean hasPrevious() {
			return nextIndex != 0;
		}

		public E previous() {
			if (nextIndex == 0)
			throw new NoSuchElementException();

			lastReturned = next = next.previous;
			nextIndex--;
			checkForComodification();
			return lastReturned.element;
		}

		public int nextIndex() {
			return nextIndex;
		}

		public int previousIndex() {
			return nextIndex-1;
		}

		public void remove() {
				checkForComodification();
				Entry<E> lastNext = lastReturned.next;
				try {
					LinkedList.this.remove(lastReturned);
				} catch (NoSuchElementException e) {
					throw new IllegalStateException();
				}
			if (next==lastReturned)
					next = lastNext;
				else
			nextIndex--;
			lastReturned = header;
			expectedModCount++;
		}

		public void set(E e) {
			if (lastReturned == header)
			throw new IllegalStateException();
			checkForComodification();
			lastReturned.element = e;
		}

		public void add(E e) {
			checkForComodification();
			lastReturned = header;
			addBefore(e, next);
			nextIndex++;
			expectedModCount++;
		}

		final void checkForComodification() {
			if (modCount != expectedModCount)
			throw new ConcurrentModificationException();
		}
    }

    private static class Entry<E> {
	E element;
	Entry<E> next;
	Entry<E> previous;

	Entry(E element, Entry<E> next, Entry<E> previous) {
	    this.element = element;
	    this.next = next;
	    this.previous = previous;
	}
    }

    private Entry<E> addBefore(E e, Entry<E> entry) {
	Entry<E> newEntry = new Entry<E>(e, entry, entry.previous);
	newEntry.previous.next = newEntry;
	newEntry.next.previous = newEntry;
	size++;
	modCount++;
	return newEntry;
    }

    private E remove(Entry<E> e) {
	if (e == header)
	    throw new NoSuchElementException();

        E result = e.element;
	e.previous.next = e.next;
	e.next.previous = e.previous;
        e.next = e.previous = null;
        e.element = null;
	size--;
	modCount++;
        return result;
    }

    /**
     * @since 1.6
     */
    public Iterator<E> descendingIterator() {
        return new DescendingIterator();
    }

    /** Adapter to provide descending iterators via ListItr.previous */
    private class DescendingIterator implements Iterator {
        final ListItr itr = new ListItr(size());
		public boolean hasNext() {
			return itr.hasPrevious();
		}
		public E next() {
			return itr.previous();
		}
		public void remove() {
			itr.remove();
		}
    }

    /**
     * Returns a shallow copy of this <tt>LinkedList</tt>. (The elements
     * themselves are not cloned.)
     *
     * @return a shallow copy of this <tt>LinkedList</tt> instance
     */
    public Object clone() {
        LinkedList<E> clone = null;
		try {
			clone = (LinkedList<E>) super.clone();
		} catch (CloneNotSupportedException e) {
			throw new InternalError();
		}

        // Put clone into "virgin" state
        clone.header = new Entry<E>(null, null, null);
        clone.header.next = clone.header.previous = clone.header;
        clone.size = 0;
        clone.modCount = 0;

        // Initialize clone with our elements
        for (Entry<E> e = header.next; e != header; e = e.next)
            clone.add(e.element);

        return clone;
    }

    /**
     * Returns an array containing all of the elements in this list
     * in proper sequence (from first to last element).
     *
     * <p>The returned array will be "safe" in that no references to it are
     * maintained by this list.  (In other words, this method must allocate
     * a new array).  The caller is thus free to modify the returned array.
     *
     * <p>This method acts as bridge between array-based and collection-based
     * APIs.
     *
     * @return an array containing all of the elements in this list
     *         in proper sequence
     */
    public Object[] toArray() {
		Object[] result = new Object[size];
        int i = 0;
        for (Entry<E> e = header.next; e != header; e = e.next)
            result[i++] = e.element;
		return result;
    }

    /**
     * Returns an array containing all of the elements in this list in
     * proper sequence (from first to last element); the runtime type of
     * the returned array is that of the specified array.  If the list fits
     * in the specified array, it is returned therein.  Otherwise, a new
     * array is allocated with the runtime type of the specified array and
     * the size of this list.
     *
     * <p>If the list fits in the specified array with room to spare (i.e.,
     * the array has more elements than the list), the element in the array
     * immediately following the end of the list is set to <tt>null</tt>.
     * (This is useful in determining the length of the list <i>only</i> if
     * the caller knows that the list does not contain any null elements.)
     *
     * <p>Like the {@link #toArray()} method, this method acts as bridge between
     * array-based and collection-based APIs.  Further, this method allows
     * precise control over the runtime type of the output array, and may,
     * under certain circumstances, be used to save allocation costs.
     *
     * <p>Suppose <tt>x</tt> is a list known to contain only strings.
     * The following code can be used to dump the list into a newly
     * allocated array of <tt>String</tt>:
     *
     * <pre>
     *     String[] y = x.toArray(new String[0]);</pre>
     *
     * Note that <tt>toArray(new Object[0])</tt> is identical in function to
     * <tt>toArray()</tt>.
     *
     * @param a the array into which the elements of the list are to
     *          be stored, if it is big enough; otherwise, a new array of the
     *          same runtime type is allocated for this purpose.
     * @return an array containing the elements of the list
     * @throws ArrayStoreException if the runtime type of the specified array
     *         is not a supertype of the runtime type of every element in
     *         this list
     * @throws NullPointerException if the specified array is null
     */
    public <T> T[] toArray(T[] a) {
        if (a.length < size)
            a = (T[])java.lang.reflect.Array.newInstance(
                                a.getClass().getComponentType(), size);
        int i = 0;
		Object[] result = a;
        for (Entry<E> e = header.next; e != header; e = e.next)
            result[i++] = e.element;

        if (a.length > size)
            a[size] = null;

        return a;
    }

    private static final long serialVersionUID = 876323262645176354L;

    /**
     * Save the state of this <tt>LinkedList</tt> instance to a stream (that
     * is, serialize it).
     *
     * @serialData The size of the list (the number of elements it
     *             contains) is emitted (int), followed by all of its
     *             elements (each an Object) in the proper order.
     */
    private void writeObject(java.io.ObjectOutputStream s)
        throws java.io.IOException {
		// Write out any hidden serialization magic
		s.defaultWriteObject();

        // Write out size
        s.writeInt(size);

		// Write out all elements in the proper order.
        for (Entry e = header.next; e != header; e = e.next)
            s.writeObject(e.element);
    }

    /**
     * Reconstitute this <tt>LinkedList</tt> instance from a stream (that is
     * deserialize it).
     */
    private void readObject(java.io.ObjectInputStream s)
        throws java.io.IOException, ClassNotFoundException {
		// Read in any hidden serialization magic
		s.defaultReadObject();

        // Read in size
        int size = s.readInt();

        // Initialize header
        header = new Entry<E>(null, null, null);
        header.next = header.previous = header;

		// Read in all elements in the proper order.
		for (int i=0; i<size; i++)
            addBefore((E)s.readObject(), header);
	}
}

  • 大小: 33.2 KB
分享到:
评论

相关推荐

    java源码程序-ov

    【Java图书管理系统源码解析】 本项目是一个基于Java语言开发的图书馆管理系统,是某大学生的毕业设计作品。作为学习和研究的资源,它提供了一整套的源代码、系统说明和程序结构文档,对于深入理解Java编程以及软件...

    ArrayList-LinkedList-源码.rar

    《ArrayList与LinkedList源码解析》 在Java编程中,ArrayList和LinkedList是两种常见的动态数组,它们都是Java集合框架的一部分,提供了对元素存储和操作的功能。本篇将深入探讨ArrayList和LinkedList的内部实现...

    Jdk1.6 Collections Framework源码解析(2)-LinkedList

    《Jdk1.6 Collections Framework源码解析(2)-LinkedList》 LinkedList是Java集合框架中的一个重要的类,它是List接口的实现,同时继承了AbstractSequentialList,并实现了Deque接口。LinkedList是一种双链表结构,...

    java源码api-java-:JAVA常用API源码解析

    "java源码api-java-"这个主题专注于讲解Java API的常用组件,帮助开发者深入理解其工作原理,提升编程技能。 Java API覆盖了多个方面,包括集合框架、IO流、多线程、网络编程、反射机制等。以下是一些关键知识点: ...

    Java源码解析LinkedList

    Java源码解析LinkedList Java源码解析LinkedList是Java集合框架中的一种重要数据结构。它是一种双向链表,具有高效的插入和删除操作。今天,我们将深入探讨LinkedList的源码,了解它的内部实现机制。 首先,让我们...

    剑指offer--java版1--10源码及解析总结.zip

    通过学习和实践《剑指Offer》中的Java源码和解析,不仅可以提升编程技能,还能加深对算法、数据结构的理解,为应对面试和日常开发工作打下坚实的基础。这份压缩包中的资料,无疑是学习和复习的宝贵材料,值得仔细...

    java-katas-源码.rar

    《Java Katas源码解析》 Java Katas是一种编程练习,旨在提升开发者在Java语言中的技能和熟练度。这些练习通常包含一系列小任务,每个任务都聚焦于特定的编程概念或技术,帮助开发者通过实践来巩固和加深理解。在...

    Java源码解析——看优秀源码最能使人进步

    Java源码解析——看优秀源码最能使人进步 Java源码解析是一种深入了解JDK源码的方式,适合那些想深入了解JDK源码的人。通过对JDK源码的解析,可以让开发者更好地理解Java语言的底层逻辑,从而写出更加高效、稳定的...

    java-learn-源码.rar

    《深入解析Java学习源码》 Java是一种广泛使用的高级编程语言,以其跨平台、面向对象、安全性高等特性深受开发者喜爱。"java-learn-源码.rar"是一个包含Java学习源码的压缩包,旨在帮助初学者和有经验的开发者更好...

    java源码解读-JavaSource:Java源码解读

    在Java编程语言的世界里,源码解读是提升技术深度、理解内部机制的关键步骤。"JavaSource:Java源码解读"项目旨在帮助开发者深入探索Java的内部...对于任何想要成为Java专家的人来说,深入源码解析都是必不可少的一环。

    java源码剖析-Java-source-code-analysis:Java数据结构的源代码分析

    Java源码剖析是一个深入理解Java数据结构实现细节的过程,这对于提升编程技能和优化代码性能至关重要。在Java中,许多常用的数据结构,如ArrayList、LinkedList、HashMap等,都是由Java标准库(Java SE中的java.util...

    java——ArrayList-源码解析.docx

    ArrayList 是 Java 中一种常用的列表类,它是 List 接口的实现,基于动态数组的数据结构。ArrayList 的核心特性在于其能够动态地调整数组的大小以适应元素数量的变化,从而提供了比传统固定大小数组更为灵活的使用...

    基于Java的源码-编写的显示器显示模式检测程序.zip

    本项目“基于Java的源码-编写的显示器显示模式检测程序”显然是一个利用Java来检测和管理显示器显示模式的实用工具。下面我们将深入探讨这个程序可能涉及的Java知识点以及显示器模式检测的相关技术。 首先,Java的...

    第三章 LinkedList源码解析1

    LinkedList源码解析 LinkedList是Java中的一种链表实现,它的底层是一个环形双向链表。在 LinkedList 中,节点之间通过引用相互连接,形成一个链表结构。LinkedList 提供了多种方法来操作链表,包括添加、删除、...

    java源码解读-ITG-JavaBook01:Java面试高频源码解读

    如ArrayList、LinkedList、HashMap、HashSet等的内部实现原理,比如它们的扩容策略、线程安全问题以及各种操作的时间复杂度分析,这些都是源码解析的重点。 三、并发编程 Java并发编程是高级面试的重要部分,涉及到...

    基于Java的实例开发源码-github-Java-api.zip

    2. **集合框架**:Java集合框架包含ArrayList、LinkedList、HashMap等数据结构,方便存储和管理对象。 3. **多线程**:Java.util.concurrent包提供了高级的线程管理和并发工具,如ExecutorService和Semaphore。 4. *...

    java源码剖析-Analysis-of-java-source-code:Java源代码

    《Java源码剖析》 Java源码剖析是一个深入探索Java编程语言核心机制的过程,它涉及到对Java类库、API以及其内部实现的详细研究。Java作为一款广泛应用的面向对象编程语言,其源代码包含了丰富的设计模式、算法和...

Global site tag (gtag.js) - Google Analytics