5.2 细菌繁殖

代码如下：

/*
*
*Declaration:The author of <<Accelerated C++>> has wrote in the end of that book: As you look for reading materimal, keep in mind that books on the shelf do not make you a better programmer. Ultimately, the only way to improve your programming is to write programs.	>这些程序来自一些ACM书籍，作者只为提高编程能力，实现书中例题或练习。如有侵权，请联系作者，作者将立即删除。
*
*联系邮箱：mingxinglai#gmail.com
*
*/

#include <stdio.h>

int main(int argc, char* argv[])
{
	int days[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
	int n;
	scanf("%d", &n);

	for( int i = 0; i < n; i++)
	{
		int month_1, day_1, month_2, day_2, num;
		scanf("%d%d%d%d%d", &month_1, &day_1, &num, &month_2, &day_2);
		int sum = 0;
		for( int k = month_1; k < month_2; k++)
			sum += days[ k - 1 ];

		sum -= day_1;
		sum += day_2;

		int  nNum = num;
		for(int  k = 0; k < sum; k++)
			nNum *= 2;

		printf("%d\n", nNum);

	}
	return 0;
}

示例2：（较上面的代码更为简洁明了）

#include <stdio.h>
int month[]= {0,31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
int main(int argc, char* argv[])
{
	int times;
	scanf("%d", ×);
	int mon1, date1, mon2, date2, num;
	while( times-- )
	{
		scanf("%d%d%d%d%d", &mon1, &date1, &num, &mon2, &date2);
		int days = date2 - date1;
		for( int i = mon1; i < mon2; i++)
			days += month[i];

		long nNum = num;
		for( int j = 0; j < days; j++)
			num *= 2;

		printf("%d\n", num);
	}
	return 0;
}