在android2.1如何实现对ssl的无证书访问？(转)

在网上看了，httpchlent的资料，httpchlent4.1可以实现对ssl的无证书访问。
实现代码为：
  SSLContext sslcontext = SSLContext.getInstance("TLS");
    sslcontext.init(null, new TrustManager[] { easyTrustManager }, null);
    SSLSocketFactory sf = new SSLSocketFactory(sslcontext);
    Scheme sch = new Scheme("https", sf, 8443);
    httpclient.getConnectionManager().getSchemeRegistry().register(sch);

但在android2.1中，SSLSocketFactory类中没有下面这个构造函数
SSLSocketFactory sf = new SSLSocketFactory(sslcontext)；

客户端不想存放安全证书，请问在android2.1如何实现对ssl的无证书访问？

解决方法如下：
public String connentUrl(String strUrl) {
  StringBuffer sbResult = null;

try {
  HttpURLConnection http = null;
  URL url = new URL(strUrl);

  // 判断是http请求还是https请求
  if (url.getProtocol().toLowerCase().equals("https")) {
     trustAllHosts();
     HttpsURLConnection https = (HttpsURLConnection) url.openConnection();
     https.setHostnameVerifier(DO_NOT_VERIFY);
     http = https;
  } else {
      http = (HttpURLConnection) url.openConnection();
  }                                              
               
  http.setDoInput(true);
  // 设置超时时间
  http.setConnectTimeout(10000);
  // 设置请求类型为post
  http.setRequestMethod("POST");
// 设置接收类型
  http.setRequestProperty("accept", "*
private static void trustAllHosts() {
     // Create a trust manager that does not validate certificate chains
     // Android 采用X509的证书信息机制
    TrustManager[] trustAllCerts = new TrustManager[] { new X509TrustManager() {
     public java.security.cert.X509Certificate[] getAcceptedIssuers() {
          return new java.security.cert.X509Certificate[] {};
   }

public void checkClientTrusted(X509Certificate[] chain, String authType) throws CertificateException {}
  public void checkServerTrusted(X509Certificate[] chain,String authType) throws CertificateException {}
}
};

// Install the all-trusting trust manager
try {
  SSLContext sc = SSLContext.getInstance("TLS");
  sc.init(null, trustAllCerts, new java.security.SecureRandom());
  HttpsURLConnection.setDefaultSSLSocketFactory(sc.getSocketFactory());
} catch (Exception e) {
  e.printStackTrace();
}
}