Struts2 与 Ext 整合开发

最近一直想找一个Struts与Ext整合的一个比较规范的做法，个人觉得必然使用Struts的json，弄了一个晚上，不知道是否在符合大众的规范，配置如下：

Struts2从2.1.7开始便将json整合进去了，从Strtus2的lib包中可以片可以找到，名为struts2-json-plugin-2.x.x.x.jar

将json-plugin放入工程的lib中去后，便可以开始进行开发：

Action：

 

package com.bjsoft.oa.action.system;
import nl.captcha.Captcha;
import org.apache.commons.lang.xwork.StringUtils;
import com.bjsoft.oa.model.User;
import com.bjsoft.oa.service.UserService;
import com.opensymphony.xwork2.ActionContext;
import com.opensymphony.xwork2.ActionSupport;
public class LoginAction extends ActionSupport {
	private static final long serialVersionUID = 2578893349737621315L;
	private UserService userService;
	private User user;
	private String simpleCaptcha;
	private boolean success;
	private String msg;
	@Override
	public String execute() throws Exception {
		success = false;
		msg = "";
		Captcha _simpleCaptcha = (Captcha) ActionContext.getContext()
				.getSession().get("simpleCaptcha");
		if (_simpleCaptcha.isCorrect(simpleCaptcha)) {
			String _userName = user.getUsername();
			String _password = user.getPassword();
			if (!StringUtils.isEmpty(_userName)
					&& !StringUtils.isEmpty(_password)) {
				User u = this.userService.getUserByName(_userName);
				if(u != null){
					if (StringUtils.equals(u.getPassword(), _password)) {
						success = true;
					} else {
						msg = "密码错误！";
					}
				}else{
					msg = "不存在的用户";
				}
				
			} else {
				msg = StringUtils.isEmpty(_userName) ? "用户名不能为空" : "密码不能为空";
			}
		} else {
			msg = "验证码错误！";
		}
		return super.execute();
	}
	public UserService getUserService() {
		return userService;
	}
	public void setUserService(UserService userService) {
		this.userService = userService;
	}
	public User getUser() {
		return user;
	}
	public void setUser(User user) {
		this.user = user;
	}
	public String getSimpleCaptcha() {
		return simpleCaptcha;
	}
	public void setSimpleCaptcha(String simpleCaptcha) {
		this.simpleCaptcha = simpleCaptcha;
	}
	public boolean isSuccess() {
		return success;
	}
	public void setSuccess(boolean success) {
		this.success = success;
	}
	public String getMsg() {
		return msg;
	}
	public void setMsg(String msg) {
		this.msg = msg;
	}
}

 

strtus.xml

 

<struts>
	<package name="login" namespace="/" extends="json-default">
		<action name="login" class="com.bjsoft.oa.action.system.LoginAction">
			<result type="json">
				<param name="includeProperties">
					success,msg
				</param>
			</result>
		</action>
	</package>
</struts>

这里的package一定要继承json-default,并且result type也是要json格式，同时另一个问题是没有参数的json result 将会把action中所有局部变量放在json格式的字符串返回给前端，这样似乎就造成了不必要的浪费，于是有两种解决办法，一种是上面的配置，告诉struts应该包含哪些变量，另一种是告诉struts不应该包含哪些变量，

<!-- Result fragment -->
<result type="json">
  <param name="excludeProperties">
    login.password,
    studentList.*\.sin
  </param>
</result>

这样就可以了。