删除数组中第i个以及i后j个元素

public class DeleteChar {

    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        char[] yourChar = new char[]{'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i'};
        yourChar = DeleteChar.delete(yourChar, 2, 3);
        System.out.println(String.valueOf(yourChar));//输出为ab    ghi
    }
    
    /*
     * 删除数组中从第i个元素以及后j个元素
     * @input targetChar[] 目标数组
     * @input i 第i个元素
     * @input j 后j个元素
     * @return 返回原来数据，其中i和i后的j个元素被' '代替，即被删除，清零成初始化状态
     */
    public static char[] delete(char[] targetChar, int i, int j)
    {
        char[] resultChar = new char[targetChar.length];
        if (targetChar.length > 0 && i > 0 && j > 0 && i + j < targetChar.length)
        {
            for (int k = 0; k < targetChar.length; k++)
            {
                if (k < i || k > (j + i))
                {
                    resultChar[k] = targetChar[k];
                }
                else
                {
                    resultChar[k] = ' ';
                }
            }
        }
        else
        {
            System.out.println("Your input is wrong!");
            System.exit(0);
        }
        
        return resultChar;
    }

}