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关于ids for this class must be manually assigned before calling save()

    博客分类:
  • j2ee
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引起问题的原因:

就是那个由Hibernate根据数据库表自动生成的"类名.hbm.xml"映射文件引起的。

首先我的表(Info)由两个字段组成,即:

int id;//主建

String name;

(自己做测试,所以就简单的建了个表)

由Hibernate生成的Info.hbm.xml中是这样写的:

-----------------------------------------------------

<id name="id" type="java.lang.Integer">
<column name="id" />
<generator class="assigned"/>
</id>

-----------------------------------------------------

<id>这个是必须有的。它是用来定义实体的标识属性(对应数据库表的主键)

而我这里由于id本身就是主键,所以column的属性便是id

下面是很关键的一点<generator>,由于一时兴趣,于是找了很多资料,关于它的解释是:用于指定主键的生成策略。它的值有多,下面是转来的:

--------------------------------------------------------------------------------

“assigned”
主键由外部程序负责生成,在 save() 之前指定一个。

“hilo”
通过hi/lo 算法实现的主键生成机制,需要额外的数据库表或字段提供高位值来源。

“seqhilo”
与hilo 类似,通过hi/lo 算法实现的主键生成机制,需要数据库中的 Sequence,适用于支持 Sequence 的数据库,如Oracle。

“increment”
主键按数值顺序递增。此方式的实现机制为在当前应用实例中维持一个变量,以保存着当前的最大值,之后每次需要生成主键的时候将此值加1作为主键。这种方式可能产生的问题是:不能在集群下使用。

“identity”
采用数据库提供的主键生成机制。如DB2、SQL Server、MySQL 中的主键生成机制。

“sequence”
采用数据库提供的 sequence 机制生成主键。如 Oralce 中的Sequence。

“native”
由 Hibernate 根据使用的数据库自行判断采用 identity、hilo、sequence 其中一种作为主键生成方式。

“uuid.hex”
由 Hibernate 基于128 位 UUID 算法 生成16 进制数值(编码后以长度32 的字符串表示)作为主键。

“uuid.string”
与uuid.hex 类似,只是生成的主键未进行编码(长度16),不能应用在 PostgreSQL 数据库中。

“foreign”
使用另外一个相关联的对象的标识符作为主键。

--------------------------------------------------------------------------------

看了上面的介绍,再看看代码,原来是<Generator>属性设置有问题。

然后改为"identity"、"native"问题便解决。

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