Hibernate构造器查询，字段中有日期报org.hibernate.hql.PARSER Unable to locate appropriate cons

解决方案：

Dao:

super.getHibernateTemplate().find("select new Student(id,name,date) from Student");

实体类：

public class Student {

private Long id;

private String name;

private String address;

private Timestamp date;

public Long getId() {
   return id;
}

public void setId(Long id) {
   this.id = id;
}

public String getName() {
   return name;
}

public void setName(String name) {
   this.name = name;
}

public String getAddress() {
   return address;
}

public void setAddress(String address) {
   this.address = address;
}

public Timestamp getDate() {
   return date;
}

public void setDate(Timestamp date) {
   this.date = date;
}

public Student() {
   super();
}

//注意些处的构造方法
public Student(Long id, String name, Object date) {

this.id=id;
   this.name = name;
   this.date = stringToTimestamp(date.toString());
}

/**
* 字符串转换为Timestamp
* @param dateStr
* @return
*/
public static Timestamp stringToTimestamp(String dateStr){
  
   SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
   Calendar cal = Calendar.getInstance();
   try {
    Date date = sdf.parse(dateStr);
    date.getTime();
    cal.setTime(date);
    return new Timestamp(cal.getTimeInMillis());
   } catch (ParseException e) {
    e.printStackTrace();
   }
  
   cal.setTime(new Date());
   return new Timestamp(cal.getTimeInMillis());
}

}