HDU 1022 Train Problem I

Train Problem I

Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6599Accepted Submission(s): 2409

Problem Description

As the new term comes, the Ignatius Train Station is very busy nowadays. A lot of student want to get back to school by train(because the trains in the Ignatius Train Station is the fastest all over the world ^v^). But here comes a problem, there is only one railway where all the trains stop. So all the trains come in from one side and get out from the other side. For this problem, if train A gets into the railway first, and then train B gets into the railway before train A leaves, train A can't leave until train B leaves. The pictures below figure out the problem. Now the problem for you is, there are at most 9 trains in the station, all the trains has an ID(numbered from 1 to n), the trains get into the railway in an order O1, your task is to determine whether the trains can get out in an order O2.

 

Input

The input contains several test cases. Each test case consists of an integer, the number of trains, and two strings, the order of the trains come in:O1, and the order of the trains leave:O2. The input is terminated by the end of file. More details in the Sample Input.

 

Output

The output contains a string "No." if you can't exchange O2 to O1, or you should output a line contains "Yes.", and then output your way in exchanging the order(you should output "in" for a train getting into the railway, and "out" for a train getting out of the railway). Print a line contains "FINISH" after each test case. More details in the Sample Output.

 

Sample Input

3 123 321
3 123 312

 

Sample Output

Yes.
in
in
in
out
out
out
FINISH
No.
FINISH


Hint
Hint
 
For the first Sample Input, we let train 1 get in, then train 2 and train 3.
So now train 3 is at the top of the railway, so train 3 can leave first, then train 2 and train 1.
In the second Sample input, we should let train 3 leave first, so we have to let train 1 get in, then train 2 and train 3.
Now we can let train 3 leave.
But after that we can't let train 1 leave before train 2, because train 2 is at the top of the railway at the moment.
So we output "No.".

 

Author

Ignatius.L

呢派比较堕落…………成日刷水题，主要系记录得太多，想清清。

尼条绝对就系一条关于堆栈既基本题目啦，就系比入栈顺序你，判断出栈顺序可能否， 我既思路就系直接模拟， 因为数据最大9。

直接贴代码都得啦：

4316615

2011-08-02 20:55:46

Accepted

1022

0MS

240K

767 B

C++

10SGetEternal{（。）（。）}!

#include <iostream>
#include <string>
#include <vector>
using namespace std;

string o1, o2;
vector<char> tra, sta;

bool sim()
{
    int i = 0, j = 0;
    tra.clear();
    sta.clear();
    while (i < o1.length() || j < o2.length())
    {
        while (!tra.empty() && tra[tra.size() - 1] == o2[j])
        {
            tra.pop_back();
            sta.push_back(1);
            j++;
        }
        if (i < o1.length())
        {
            tra.push_back(o1[i++]);
            sta.push_back(0);
        }else break;
    }
    if (j == o2.length()) return 1;
    else return 0;
}

int main()
{
    int n;
    
    while (cin >> n >> o1 >> o2)
    {
        if (sim())
        {
            puts("Yes.");
            for (n = 0; n < sta.size(); n++)
                if (sta[n]) puts("out");
                else puts("in");
        }
        else puts("No.");
        printf("FINISH\n");
    }

    return 0;
}

再做多一条水题就开始黎真嘎啦…………