JAX-RS之resteasy跟spring整合

  其实,在JAX-RS标准下,jboss的resteasy跟spring结合的话,无非是如何去取得
spring中的bean而已.两个方法,例子如下

1 比如有个接口和实现类

public interface CustomerBo{
 
	String getMsg();
 
}

  实现类
  

public class CustomerBoImpl implements CustomerBo {
 
	public String getMsg() {
 
		return "RESTEasy + Spring example";
 
	}

applicationContext.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd ">

<bean id="customerBo" class="com.mkyong.customer.impl.CustomerBoImpl">
        </bean>

</beans>


之后用WebApplicationContextUtils + ServletContext

引用

@Path("/customer")
public class PrintService {

CustomerBo customerBo;

@GET
@Path("/print")
public Response printMessage(@Context ServletContext servletContext) {

//get Spring application context
ApplicationContext ctx =
                     WebApplicationContextUtils.getWebApplicationContext(servletContext);
customerBo= ctx.getBean("customerBo",CustomerBo.class);

String result = customerBo.getMsg();

return Response.status(200).entity(result).build();

}

 
第2种方法,自己写类,实现ApplicationContextAware ,当然这个类要单例
 

import org.springframework.beans.BeansException;
import org.springframework.context.ApplicationContext;
import org.springframework.context.ApplicationContextAware;
 
public class SpringApplicationContext implements ApplicationContextAware {
 
	private static ApplicationContext appContext;
 
	// Private constructor prevents instantiation from other classes
        private SpringApplicationContext() {}
 
	@Override
	public void setApplicationContext(ApplicationContext applicationContext)
			throws BeansException {
		appContext = applicationContext;
 
	}
 
	public static Object getBean(String beanName) {
		return appContext.getBean(beanName);
	}
 
}

  applicationContext.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd ">

<bean class="com.mkyong.context.SpringApplicationContext"></bean>

<bean id="customerBo" class="com.mkyong.customer.impl.CustomerBoImpl">
        </bean>

</beans>

使用:
 

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.core.Response;
import com.mkyong.context.SpringApplicationContext;
import com.mkyong.customer.CustomerBo;
 
@Path("/customer")
public class PrintService {
 
	CustomerBo customerBo;
 
	@GET
	@Path("/print")
	public Response printMessage() {
 
		customerBo = (CustomerBo) SpringApplicationContext.getBean("customerBo");
 
		String result = customerBo.getMsg();
 
		return Response.status(200).entity(result).build();
 
	}
 
}

    web.xml整合
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Restful Web Application</display-name>

<context-param>
<param-name>resteasy.resources</param-name>
<param-value>com.mkyong.rest.PrintService</param-value>
</context-param>

<listener>
<listener-class>
org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap
                </listener-class>
</listener>

<listener>
<listener-class>
                        org.springframework.web.context.ContextLoaderListener
                </listener-class>
</listener>

<servlet>
<servlet-name>resteasy-servlet</servlet-name>
<servlet-class>
org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher
                </servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>resteasy-servlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>

</web-app>

评论

2 楼 ruijin5566 2012-07-26  

学习了，在项目里用了

1 楼 grassking 2012-01-04  

resteasy中能通过@Autowrited注解来获取bean吗？